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2 years ago

I need info on Albert Einstein

2 answers:

4 0

<span>Born on March 14, 1879 in Ulm, Württemberg, Germany, Albert Einstein grew up in a secular Jewish family. ... Einstein had one sister, Maja, born two years after him.Einstein attended elementary school at the Luitpold Gymnasium in Munich.</span>

Slav-nsk [51]2 years ago

3 0

Just use wiki! I tried to post the website, but it removes it! Sorry!

You might be interested in

Direct Variation: If y = -16, when x = 4, find x when y = -96.

Andrews [41]

Answer:

x = 24

Step-by-step explanation:

y= -16

-16 x 6 = -96

y= -96

x= 4

4 x 6 = 24

x=24

3 0

2 years ago

What is 17 less than a number g?

Sophie [7]

I hope this helps you

17-g

8 0

2 years ago

Read 2 more answers

Which expression is equivalent to 5x+10y-15?

Papessa [141]

Answer:

Step-by-step explanation:

I think it's 5(x+2y-3)

5 0

2 years ago

V square+6v-59=0<br> answer in one equation

Tema [17]

X= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$
a=1
b=6
c=-59
x= $\frac{-6+/- \sqrt{(6)-4(1)(-59)} }{2(1)}$
x= $-3+ 2\sqrt{17}$ and $-3- 2\sqrt{17}$

8 0

2 years ago

Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En

Sergio [31]

Answer:

$\bold{cot(t) =\dfrac{12}{5}}$

Step-by-step explanation:

Given that:

$Cosec (t) = -\frac{13}5$

for $\pi < t < \frac{3 \pi}2$

That means, angle $t$ is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

$cosec^2\theta -cot^2\theta =1$

here, $\theta =t$

So, $cosec^2t-cot^2t=1$

$\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}$

But, angle $t$ is in 3rd quadrant, so value of

$\bold{cot(t) =\dfrac{12}{5}}$

4 0

2 years ago