All categories

2 years ago

A sound wave has a frequency of 425 Hz. What is the period of this wave

Physics

1 answer:

Oduvanchick [21]2 years ago

5 0

Answer: The time period of the given wave with frequency of 425 Hertz is 0.0023 seconds.

Explanation:

Frequency of the wave = 425 Hertz = $425 sec^{-1}$

$\text{Time period}=\frac{1}{Frequency}$

$\text{Time period}==\frac{1}{425 sec^{-1}}=0.0023 sec$

The time period of the given wave with frequency of 425 Hertz is 0.0023 seconds.

You might be interested in

Unscramble the bolded letters to guess the 6 letter word code. Did you get the poses or exercises correct? MOUNTAIN POSE TRIANGL

nikitadnepr [17]

Explanation:

I don't see a question...

8 0

2 years ago

An artificial satellite is in a circular orbit around a planet of radius r= 2.05 x103 km at a distance d 310.0 km from the plane

lubasha [3.4K]

Answer:

$\rho = 12580.7 kg/m^3$

Explanation:

As we know that the satellite revolves around the planet then the centripetal force for the satellite is due to gravitational attraction force of the planet

So here we will have

$F = \frac{GMm}{(r + h)^2}$

here we have

$F =\frac {mv^2}{(r+ h)}$

$\frac{mv^2}{r + h} = \frac{GMm}{(r + h)^2}$

here we have

$v = \sqrt{\frac{GM}{(r + h)}}$

now we can find time period as

$T = \frac{2\pi (r + h)}{v}$

$T = \frac{2\pi (2.05 \times 10^6 + 310 \times 10^3)}{\sqrt{\frac{GM}{(r + h)}}}$

$1.15 \times 3600 = \frac{2\pi (2.05 \times 10^6 + 310 \times 10^3)}{\sqrt{\frac{(6.67 \times 10^{-11})(M)}{(2.05 \times 10^6 + 310 \times 10^3)}}}$

$M = 4.54 \times 10^{23} kg$

Now the density is given as

$\rho = \frac{M}{\frac{4}{3}\pi r^3}$

$\rho = \frac{4.54 \times 10^{23}}{\frac{4}[3}\pi(2.05 \times 10^6)^3}$

$\rho = 12580.7 kg/m^3$

8 0

2 years ago

3. What will happen to the black bass and blue gill as the floor of the ponds fills with organic

yKpoI14uk [10]

Answer: die

Explanation: oyxagan all goon bc of all dat suffs

8 0

2 years ago

A steel cable with Cross Sectional Area 3.00cm² has an elastic limit of 2.40 x 10^8pascals. Find the maximum upward acceleration

bazaltina [42]

Answer:

Stress = F / A force per unit area

A = 3.00 cm^2 = 3 E-4 m^2

F = 2.4E8 N/m^2 * 3E-4 m^2 = 7.2E4 N max force applied

F/3 = 2.4E4 N if force not to exceed limit (= f)

f = M a

a = 2.4 E4 N / 1.2 E3 kg = 20 m / s^2 about 2 g

3 0

3 years ago

If earth had no landmasses, then the idealized zonal precipitation pattern would have _______.

inysia [295]

If the planet earth has no land masses, the idealized zonal precipitation pattern would likely have regions that are wet in the equator and there will be more of mid-latitudes if the earth has no land masses at all and it does not exist.

7 0

3 years ago