I think the answer is discovery.
Thw question is not complete. The complete question is;
Charge of uniform linear density (6.7 nCim) is distributed along the entire x axis. Determine the magnitude of the electric field on the y axis at y = 1.6 m. a. 32 N/C b. 150 NC c 75 N/C d. 49 N/C e. 63 NC
Answer:
Option C: E = 75 N/C
Explanation:
We are given;
Uniform linear density; λ = 6.7 nC/m = 6.7 × 10^(-9) C/m
Distance on the y-axis; d = 1.6 m
Now, the formula for electric field with uniform linear density is given as;
E = λ/(2•π•r•ε_o)
Where;
E is electric field
λ is uniform linear density = 6.7 × 10^(-9) C/m
r is distance = 1.6m
ε_o is a constant = 8.85 × 10^(-12) C²/N.m²
Thus;
E = (6.7 × 10^(-9))/(2π × 1.6 × 8.85 × 10^(-12))
E = 75.31 N/C ≈ 75 N/C
<span>All of the following were barriers to minority participation in early psychology except school desegregation. The correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer that you were looking for and the answer has come to your great help.</span>
Answer: 490N
Explanation:
Newton is the unit for force. Force = mass x acceleration
F=N m=50kg a=9.8 (earth's acceleration of gravity)
F=50X9.8
F≈490N
Derive relation F = ma from Newton 2nd Law of Motion. Let us derive the relation of force F = ma from Newton's second law: ... It means that the linear momentum will change faster when a bigger force is applied. Consider a body of mass 'm' moving with velocity v.
