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Fudgin [204]
3 years ago
8

If m∠1 = 3x, m∠3 = 2x + 20 and m∠5 = 30, what is the value of x?

Mathematics
1 answer:
Nikolay [14]3 years ago
8 0

Answer:

50 degrees

Step-by-step explanation:

The diagram is attached below.

Theorem: The Exterior angle of a triangle is equal to the sum of two opposite interior angles.

By the theorem stated above:

m∠3+m∠5=m∠1

2x+20+30=3x

3x-2x=50

x=50

The value of x is 50 degrees.

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Find the formula for an exponential function that passes through the two points give.
Ksenya-84 [330]

Answer:

y=3(2)^{x}

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Given.

Two points are given.

(x, y)=(-1,\frac{3}{2}) and (x, y)=(3,24)

An exponential function is in the general form.

y=a(b)^{x}-------(1)

We know the points  (-1,\frac{3}{2}) and (3,24)

put the first point value in equation 1

\frac{3}{2}=a(b)^{-1}

\frac{3}{2}=\frac{a}{b}

a=\frac{3}{2}\times b--------(2)

put the second point value in equation 1

24=a(b)^{3}----------(3)

Put the a value from equation 2 to equation 3

24=\frac{3}{2}\times b(b)^{3}

b^{3+1}=\frac{24\times 2}{3}

b^{4} = 16\\b=\sqrt[4]{16} \\b=2

Put the b value in equation 2

a=\frac{3}{2}\times 2

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Put the a and b value in equation 1

y=3(2)^{x}

So, the exponential function that passes through the points  (-1,\frac{3}{2}) and (3,24)) are y=3(2)^{x}.

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