Answer:
V1 = 60 km/h
V2 = 40 Km/h
Step-by-step explanation:
The speed of an object is defined as
Speed = distance / time
Let
V1 be the speed of the faster car
V2 be the speed of the other car
t1 the time it took for the first car to arrive
t2 the time it took for the second car to arrive
d1 the distance traveled by first car
d2 the distance traveled by second car
We know thanks to the problem that
V1 = V2 + 20 Km/h
t1 = t2 - 1 hour
d1 = d2 = 120 Km
d1 = V1 * t1
d2 = V2* t2
V1 * t1 = V2* t2
V1* t1 = (V1 -20)*(t1 +1)
The system of equations
(V1 -20)*(t1 +1) = 120
V1 * t1 = 120
120 + (120/t1) -20*t1 = 140
(120/t1) -20*t1 = 20
Which gives,
t1 = 2
This means
V1 = 60 km/h
V2 = V1 - 20 Km/h = 40 Km/h
Answer:
A frequency table and a line plot show which value occurs most often. this is done by labeling every value. The person can clearly see the organized layedout numbers in a frequency table or line plot.
Step-by-step explanation:
If you have any questions feel free to ask in the comments.
Answer:
Translation (moving the figure) will map figure 1 onto figure 2 and then after this , dilation by a scale factor of "2"
Answer:
t = -1, 2
Step-by-step explanation:
Step 1: Define
h(t) = -5t² + 5t + 10
Step 2: Factor
h(t) = -5(t² - t - 2)
h(t) = -5(t - 2)(t + 1)
Step 3: Find roots
0 = -5(t - 2)(t + 1)
0 = (t - 2)(t + 1)
t - 2 = 0
t = 2
t + 1 = 0
t = -1
