(3, -3); m = -2<br> In standard form

Randomly selecting a seventh grader from a school that has 250 sixth graders, 225 seventh graders, and 275 eighth graders

Alla [95]

250 + 225 + 275 = 750 in total so 1/750

5 0

3 years ago

Read 2 more answers

8. A contractor plans to brace a radio antenna with another cable. Cable X is already attached to the antenna at a height of 60

Agata [3.3K]

Answer:

142

Step-by-step explanation:

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8 0

3 years ago

If the circle has the same diameter as the edge length of the square, then the area of this circle is ___________the area of the

WINSTONCH [101]

Answer:

The area of this circle is $(\frac{\pi}{2} )$ the area of the square.

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

Step-by-step explanation:

Area of the circle is given by;

$A_c = \frac{\pi d^2}{4}$

Area of the square is given by;

$A_s = L^2$

relationship between the edge length of the square, d, and length of its side, L,

$d = \sqrt{L^2 + L^2} \\\\d = \sqrt{2L^2}$

But area of the square , $A_s = L^2$

$d = \sqrt{2A_s}$

Then, the area of the square in terms of the edge length is given by;

$A_s = \frac{d^2}{2}$

Area of the circle in terms of area of the square is given by;

$A_c = \frac{\pi d^2}{4} = \frac{\pi}{2}(\frac{d^2}{2} )\\\\But \ A_s = \frac{d^2}{2} \\\\A_c = \frac{\pi}{2}(\frac{d^2}{2} )\\\\A_c = \frac{\pi}{2}(A_s )$

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Ф = E.A

Flux through the surface of the circle is given by;

$\phi _{circle} = E.(\frac{\pi d^2}{4})$

Flux through the surface of the square is given by;

$\phi _{square} = E.(\frac{d^2}{2} )\\\\\phi _{square} =E.(\frac{d^2}{2} ).(\frac{\pi}{2} ).(\frac{2}{\pi} )\\\\\phi _{square} =E.(\frac{\pi d^2}{4} ).(\frac{2}{\pi} )\\\\\phi _{square} =(\phi _{circle}).(\frac{2}{\pi} )$

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

5 0

4 years ago

I NEED HELP BEFORE 10:00 A.M!

s344n2d4d5 [400]

Answer:

A. = 20 in²

B. = 45 ft²

C. = 29.5 ft²

D. = 36 ft²

E. = 28 ft²

Step-by-step explanation:

A. Formula = A = (h_b b)/2 = base 10 ft height_b= 4ft = 20 ft²

B. We have a rectagnle and a triangle: Formula: A = lw

= A = 30 ft² and now the triangle with the same formula as above: A = 15 ft²

30 ft²+15 ft² = 45 ft²

C. we have 2 rectagnle and a triangle: First the small recangle: A= lw = A = 1ft x 2ft = 2ft²

Second rectangle: 5 ft x 4 ft = 20 ft²

Right angeled triangle Formula: (ab)/2 = 3 ft x 5 ft = 7.5 ft²

Add it all together: 2ft²+20ft²+7.5ft² = 29.5 ft²

D. is a rectangle and a triangle: 8 ft x 3 ft = 24ft²

the triangle 8 ft x 2ft = 12 ft²; add 24 ft²+12 ft² = 36ft²

E. is a right-angled triangle (see fromula above) = (14 ft x 4 ft)/2 = 28ft²

7 0

3 years ago

25PTS!!!! PLEASE HELP!!!! WILL GIVE BRAINLIEST!!!!

AleksAgata [21]

Answer:

The answer is B.

Step-by-step explanation:

You have to have a straight line and it has to go through the origin or else its not proportional

7 0

3 years ago

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(3, -3); m = -2 In standard form