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Tema [17]
3 years ago
9

1/2= ?/30 what is the number missing?

Mathematics
1 answer:
KIM [24]3 years ago
5 0

Answer:

15/30

Step-by-step explanation:

Simple just find out what half of 30 is, which is 15. Hope this helped you.

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URGENT!!!! Find the m<2.
Leto [7]

Answer:

Hello! :) I hope I’m correct!!

Step-by-step explanation:

<em>I think the answer should be the second one.</em>

<u><em>the angle with the square at the corner is obviously a right angle, 90°. opposite angles have the same angle so opposite to it, angle 3 is also 90°. then add the angle 3 and the given angle (23°). 90°+23°=113° then subtract it to 180° (since a straight line is 180°). 180°-113°=67°</em></u>

<em />

<em>The steps:</em>

<em>To solve m< 2,</em>

<em />m< 2 = 180 - (90 + 23)<em />

<em />m< 2 = 180 - 113<em />

<em />m< 2 = 67<em />

<em />

<h3><em>Therefore, I think the answer should be 67 (second choice)</em></h3>

<em>i’m not really sure if this is the answer, but I hope this was helpful!! :)</em>

<em>if you have any questions about these steps, feel free to ask!</em>

<em>by: BrainlyAnime! ^-^</em>

<em>~Thank you!! Have a great day! ~</em>

5 0
4 years ago
Write the polynomial in factored form as a product of linear factors:
Harman [31]

Answer:

Step-by-step explanation:

p(A) = a^3 + 3a^2 + 9a + 27

put brackets around the 1st and second terms and another set around the 3rd and 4th

P(a)= (a^3 + 3a^2) + (9a + 27)

Using the distributive property, pull out the common factor for each of the 2 terms that contain the brackets.

P(a) = a^2 ( a + 3) + 9(a + 3)

Let a + 3 = x

P(a) = a^2x + 9x

Put brackets around these 2 terms

P(a)= x(a^2 + 9)

Substitute a + 3 for x

P(a) = (a + 3) ( a^2 + 9)

8 0
3 years ago
Identify the values of P, r ,and n in the expression P(1 + r/n)^nt based on the verbal description of the Emma's situation. Then
finlep [7]

Answer:

300(1.0125)^12t

Step-by-step explanation:

P=300

R=0.15

N=12

substitute them into the equation P(1+r/n)^nt and then simplify the equation. The answer should be 300(1.0125)^12t

8 0
3 years ago
Only problem 6a. Can someone demonstrate how to do this so I can do the rest solo?
Lisa [10]

as far as I can tell, is simply asking to write two more expressions, that are equivalent to the provided one, namely, grab the provided one and expand it, if you simplify the expanded version, you'd end up with the provided, for example

\bf \boxed{6a.1}~\hfill  \stackrel{changing}{\cfrac{29\cdot 3}{30\cdot 3}}\implies \stackrel{one}{\cfrac{87}{90}}~\hfill  \stackrel{changing}{\cfrac{29\cdot 7}{30\cdot 7}}\implies \stackrel{t wo}{\cfrac{203}{210}}\\\\\\\boxed{6a.3}~\hfill \stackrel{ch anging}{\cfrac{15\div 3}{30\div 3}}\implies \stackrel{one}{\cfrac{5}{10}}~\hfill \stackrel{changing}{\cfrac{15\div 5}{30\div 5}}\implies \stackrel{two}{\cfrac{3}{6}}

so let's do 6a1, 6a3 and 6a5.

\bf \boxed{6a.1}~\hfill \stackrel{changing}{\cfrac{29\cdot 3}{30\cdot 3}}\implies \stackrel{one}{\cfrac{87}{90}}~\hfill \stackrel{changing}{\cfrac{29\cdot 7}{30\cdot 7}}\implies \stackrel{t wo}{\cfrac{203}{210}} \\\\\\ \boxed{6a.3}~\hfill \stackrel{changing}{\cfrac{15\div 3}{30\div 3}}\implies \stackrel{one}{\cfrac{5}{10}}~\hfill \stackrel{changing}{\cfrac{15\div 5}{30\div 5}}\implies \stackrel{two}{\cfrac{3}{6}}

\bf \boxed{6a.5}~\hfill \stackrel{changing}{(9\cdot 10)\div (2\cdot 10)}\implies \stackrel{one}{90\div 20}~\hfill \stackrel{changing}{(9\cdot 70)\div(2\cdot 70)}\implies \stackrel{two}{630\div 140}

3 0
3 years ago
Pls help me with my homework I need it for tomorrow
mel-nik [20]
The answer is 8 feet
4 0
4 years ago
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