Answer:
2.5m/s^2
Explanation:
Step one:
given
distance = 20meters
time = 2 seconds
initial velocity u= 0m/s
let us solve for the final velocity
velocity = distance/time
velocity= 20/2
velocity= 10m/s
divide both sides by 40
A measure of the pull of gravity on an object.
1 answer:
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Answer:
The distance covered by puck A before collision is
Explanation:
From the question we are told that
The label on the two hockey pucks is A and B
The distance between the two hockey pucks is D 18.0 m
The speed of puck A is
The speed of puck B is
The distance covered by puck A is mathematically represented as
=>
The distance covered by puck B is mathematically represented as
=>
Since the time take before collision is the same
substituting values
=>
=>
Answer:
0.0334N
Explanation:
Given parameters:
M1 = 5 x 10⁶kg
M2 = 1 x 10⁶kg
Distance = 100m
Unknown:
Gravitational force = ?
Solution:
To solve this problem, we use the Newton's law of universal gravitation.
Fg =
G is the universal gravitation constant
m is the mass
r is the distance
Fg = = 0.0334N