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BaLLatris [955]
2 years ago
7

A dog running at 10 m/s is 30m behind a rabbit moving at 5 m/s. when will the dog catch up with the rabbit assuming both their v

elocities remain constant during the chase?
Physics
1 answer:
dedylja [7]2 years ago
7 0

The will dog catch up with the rabbit in 6 minutes assuming both their velocities remain constant during the chase.

<h3>What time will the dog catch the rabbit?</h3>

The time that the dog will catch up with the rabbit is given as follows:

Let the distance covered by the rabbit be x.

Distance covered by dog = x + 30

  • Time taken = distance/speed

The time taken will be the same T

  1. Time taken by dog, T = (x + 30)/10
  2. Time taken by rabbit, T = x/5

Equating both times.

(x + 30)/10 = x/5

x = 30 m

Solving for T in equation (ii);

T = 30/5 = 6 minutes

In conclusion, time is obtained as a ratio of distance and speed.


Learn more about time and speed at: brainly.com/question/26046491

#SPJ1

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Diano4ka-milaya [45]

<em>For this case we have that by definition, the social sciences group all the scientific disciplines whose object of study is linked to the activities and behavior of human beings. The social sciences, therefore, analyze the manifestations of society, both material and symbolic.</em>

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3 0
3 years ago
Two 4.3546 cm x 4.3546 cm square aluminum electrodes, spaced 0.6408 mm apart are connected to a 73.68 V battery. What is the cap
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Answer:

Capacitance, C = 26.1 picofarad

Explanation:

It is given that,

Side of square, x = 4.3546 cm = 0.043546 m

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Capacitance of parallel plates is given by :

C=\dfrac{\epsilon_oA}{d}

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C=2.61\times 10^{-11}\ F

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3 0
3 years ago
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pogonyaev

Answer:

True

Explanation:

As the formula for magnitude of a vector v and their components v_1, v_2, v_3, v_4,..., v_n is

v^2 = v_1^2 + v_2^2 + ... +v_n^2

Since v_1^2, v_2^2, v_3^2, v_4^2,..., v_n^2 \geq 0, this means the sum of them, v^2, is always greater or equal to v_1^2, v_2^2, v_3^2, v_4^2,..., v_n^2

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