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BaLLatris [955]
2 years ago
7

A dog running at 10 m/s is 30m behind a rabbit moving at 5 m/s. when will the dog catch up with the rabbit assuming both their v

elocities remain constant during the chase?
Physics
1 answer:
dedylja [7]2 years ago
7 0

The will dog catch up with the rabbit in 6 minutes assuming both their velocities remain constant during the chase.

<h3>What time will the dog catch the rabbit?</h3>

The time that the dog will catch up with the rabbit is given as follows:

Let the distance covered by the rabbit be x.

Distance covered by dog = x + 30

  • Time taken = distance/speed

The time taken will be the same T

  1. Time taken by dog, T = (x + 30)/10
  2. Time taken by rabbit, T = x/5

Equating both times.

(x + 30)/10 = x/5

x = 30 m

Solving for T in equation (ii);

T = 30/5 = 6 minutes

In conclusion, time is obtained as a ratio of distance and speed.


Learn more about time and speed at: brainly.com/question/26046491

#SPJ1

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faltersainse [42]
The last choice is correct, in order to have kinetic energy a object must be in motion, if not then the object has no kinetic energy
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Simple. Divide 500 by 764 to get 0.654 HP. 
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An iron sphere with a mass of 75.00 g is heated to a temperature of 385.0°c. it is then placed in a beaker containing 150.0 g h
gizmo_the_mogwai [7]

Question one the answer is 339 kj

Question two the answer is 9.02 kj

Question three - No

5 0
3 years ago
A force does work on a 50 g particle as the particle moves along the following straight paths in the xy-plane: 25 J from (0 m, 0
vfiekz [6]

1) Yes, it is a conservative force

2) The potential energy at (5m, 5m) is 20 J

Explanation:

1)

A force is defined to be conservative if the work done by the force when moving an object does not depend on the path taken, but only on the initial and final position of the object.

Let's verify if this condition is met for the force in this problem:

- For going from (0 m, 0 m) to (5 m, 5 m), the work done is 20 J (A)

Then we can go from (0 m, 0 m) to (5 m, 5 m) through a different path:

- from (0 m, 0 m) to (5 m, 0 m) (work done: 25 J)

- from (5 m, 0 m) to (5 m, 5 m) (work done: -5 J)

Total work done in the second path: 25 J + (-5 J) = 20 J --> same as (A)

We can also go from (0 m, 0 m) to (5 m, 5 m) through a different path:

- from (0 m, 0 m) to (0 m, 5 m) (work done: 35 J)

- from (0 m, 5 m) to (5 m, 5 m) (work done: -15 J)

Total work done in the third path: 35 J + (-15 J) = 20 J --> same as (A)

So, the force is conservative, since the work done does not depend on the path taken.

2)

For a conservative force, the change in potential energy of the object moved by the force is equal to the work done by the force in moving the object from A to B.

Here have:

Point A: (0m, 0m)

Point B: (5m, 5m)

So, the change in potential energy is equal to the work done from A to B:

W=\Delta U = U_B-U_A

where

U_B is the potential energy in point B

U_A is the potential energy in point A

In this problem, the potential energy at the origin (point A) is zero, so

U_A = 0

Also we know that the work done is

W = 20 J

So, we find

U_B = W+U_A = 20 + 0 = 20 J

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

6 0
3 years ago
6-A man standing in a valley between two parallel mountains fires a gun and hears echo at an interval of 2.
DENIUS [597]

Answer:

(a) 918.5 m

(b) 334 m from the nearest mountain and 584.5 m from the furthest mountain

Explanation:

Echo is a reflected sound so the time taken is for twice the actual distance

Let the distance between the nearest mountains and man = x m

and the distance between furthest mountains and man = y m

Distance between two mountains = ( x + y ) m

Total distance covered by sound to produce first echo

= 2x m and time = 2 sec

=> 2y = 334 x 2

=> x =(334 x 2)/2 = 334 m

Total distance covered by sound to produce 2nd echo = 2y m and time = 3.5 sec

=> 2y = 334 x x 3.5

=> y = (334 x 3.5)/2 = 584.5 m

So, Distance b/w two clif = ( 334 + 584.5) = 918.5 m

(b)

The location

The man is 334 m from the nearest mountain and 584.5 m from the furthest mountain

7 0
3 years ago
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