Answer:
they r schooling fish
Explanation:
they need to be kept in groups of 5.
4000 seconds
Explanation:
speed = distance / time
0.0004m/s = 1.6m / time
Subject time
time = 1.6 / 0.0004
time = 4000 seconds.
Hope this helps. Mark as brainliest if possible. tks
Answer:
![K_e_q=22.75878093\frac{N}{m}](https://tex.z-dn.net/?f=K_e_q%3D22.75878093%5Cfrac%7BN%7D%7Bm%7D)
![f=1.363684118Hz](https://tex.z-dn.net/?f=f%3D1.363684118Hz)
Explanation:
In order to calculate the equivalent spring constant we need to use the next formula:
![\frac{1}{K_e_q} =\frac{1}{K_1} +\frac{1}{K_2} +\frac{1}{K_3} +\frac{1}{K_4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BK_e_q%7D%20%3D%5Cfrac%7B1%7D%7BK_1%7D%20%2B%5Cfrac%7B1%7D%7BK_2%7D%20%2B%5Cfrac%7B1%7D%7BK_3%7D%20%2B%5Cfrac%7B1%7D%7BK_4%7D)
Replacing the data provided:
![\frac{1}{K_e_q} =\frac{1}{113} +\frac{1}{65} +\frac{1}{102} +\frac{1}{101}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BK_e_q%7D%20%3D%5Cfrac%7B1%7D%7B113%7D%20%2B%5Cfrac%7B1%7D%7B65%7D%20%2B%5Cfrac%7B1%7D%7B102%7D%20%2B%5Cfrac%7B1%7D%7B101%7D)
![K_e_q=22.75878093\frac{N}{m}](https://tex.z-dn.net/?f=K_e_q%3D22.75878093%5Cfrac%7BN%7D%7Bm%7D)
Finally, to calculate the frequency of oscillation we use this:
![f=\frac{1}{2(pi)} \sqrt{\frac{k}{m} }](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B1%7D%7B2%28pi%29%7D%20%5Csqrt%7B%5Cfrac%7Bk%7D%7Bm%7D%20%7D)
Replacing m and k:
![f=\frac{1}{2(pi)} \sqrt{\frac{22.75878093}{0.31} } =1.363684118Hz](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B1%7D%7B2%28pi%29%7D%20%5Csqrt%7B%5Cfrac%7B22.75878093%7D%7B0.31%7D%20%7D%20%3D1.363684118Hz)
Answer:
The frequency of watering
Explanation:
The manipulated variable in this case is the frequency of adding water to the experimental plants.
While the first plant can be said to have a watering frequency of a day, the second had a watering frequency of 2 days while the third plant had a watering frequency of 3 days.
The experiment must have been set up to determine the effects of frequency of watering on the growth of tomato plants.