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3 years ago

Which is of the following geometric solids has 5 faces and 6 vertices

Mathematics

1 answer:

lianna [129]3 years ago

3 0

i know a triangular prism has 5 faces and six vertices if that helps

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Select the correct answer.

Readme [11.4K]

Answer:

A. 52 units

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2 years ago

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Solve the following equation: 2x – 4 = 4x +8. Make sure to not only solve the problem, but to list out the steps using academic

USPshnik [31]

Answer: x = -6

Step 1: 2x = 4x+8+4
Step 2: 2x-4x = 12
Step 3: -2x = 12
Step 3: x = -6

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3 years ago

The Flu has spread throughout a town. The function below determines how many people have the flu where t=time in days and f(t)=

Gelneren [198K]

Answer:

sorry I don't have the answer right now but ill let you know

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2 years ago

Evaluate (625/16)^1/4.Please answer correctly as soon as possible

podryga [215]

Answer:

$= \frac{5}{2} = 2 \frac{1}{2}$

Step-by-step explanation:

$( \frac{625}{16} {)}^{ \frac{1}{4} } \\ \sqrt[4]{ \frac{625}{16} } = \frac{ \sqrt[4]{625} }{ \sqrt[4]{16} } \\ \frac{ \sqrt[4]{ {5}^{4} } }{ \sqrt[4]{16} } = \frac{ \sqrt[4]{ {5}^{4} } }{ \sqrt[4]{ {2}^{4} } } = \frac{5}{2}$

$\boxed{\green{= \frac{5}{2} = 2 \frac{1}{2}}}$

4 0

3 years ago

Foggy Optics, Inc., makes laboratory microscopes. Setting up each production run costs $2500. Insurance costs, based on the aver

Ray Of Light [21]

Answer: 4

Step-by-step explanation:

Let N be the total number of runs.

The microscopes per year will be equal to the total number of runs * microscopes per run

total number of microscopes = total number of runs * microscopes per run

now we have each run to cost 2500, therefore:

run costs = 2500 * total runs = 2500*N

we also have insurance and storage costs (note the average thats why we divide by 2):

storage costs = 20* microscopes per run /2 = 20*N/2

insurance costs = 15 * microscopes per run = 15*N

the costs are:

costs = run costs + storage + insurance

now the comany sells 1600 microscopes a year, so in order to figure out the number of microscopes per run we divide 1600 by the total number of runs N and replace in the costs

costs = 2500N + 40000/N => C(N) = 2500N + 40000/N

now derivate the function with respect to N and equal to 0:

$\frac{d}{dN}(2500N + 40000/N) = 2500(1-16/N^2) \\\\ 2500(1-16/N^2) = 0\\$

this gives you two solutions, N = -4 which is not eligible (you cant make negative microscopes lol) and N = 4 which is the answer

have a nice day

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3 years ago