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timofeeve [1]
3 years ago
5

What is the oxidation number of S in Li¿SOÁ? A +1 B +2 C +5 D +6

Chemistry
1 answer:
erma4kov [3.2K]3 years ago
6 0
The oxidation of S in Li2SO4:

SO4 -2

oxidation number of O is -2, so the oxidation number of O4 is -8. To make the overall charge (-2), the charge of S must be +6. The answer is (D) +6
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Which of the following describes the formation of an ionic bond?
Marysya12 [62]
Redox Reaction is an ionic bond
4 0
3 years ago
How many grams of H 2O are produced from 28.8 g of O 2? (Molar Mass of H 2O = 18.02 g) (Molar Mass of O 2=32.00 g) 4 NH 3 (g) +
krek1111 [17]

Answer:  13.9 g of H_2O will be produced from the given mass of oxygen

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} O_2=\frac{28.8g}{32.00g/mol}=0.900moles

The balanced chemical reaction is:

4NIO_2(g)+7O_2(g)\rightarrow 4NO_2(g)+6H_2O(g)

According to stoichiometry :

7 moles of O_2 produce =  6 moles of H_2O

Thus 0.900 moles of O_2 will produce =\frac{6}{7}\times 0.900=0.771moles  of H_2O

Mass of H_2O=moles\times {\text {Molar mass}}=0.771moles\times 18.02g/mol=13.9g

Thus 13.9 g of H_2O will be produced from the given mass of oxygen

5 0
3 years ago
Which elements have the quantum numbers (4,3,-2,+1/2) and (5,2,-1,-1/2)
nikklg [1K]

The elements are samarium (Sm) and silver (Ag).  

<em>Quantum numbers (4,3,-2,+½)  </em>

<em>n</em> = 4: Principal quantum number = 4.  

<em>l</em> = 3: Element has 4f electrons  

It is <em>conventional</em> to list quantum numbers in decreasing order.  

<em>Hund’s rule </em>states that all the orbitals must be half-filled with electrons having the same spin before any can receive a second electron.  

We get the following table:  

<u>Element </u><em><u>n</u></em><u> </u><em><u>l</u></em><u>   </u><em><u>m</u></em><u>ₗ </u><em><u>m</u></em><u>ₛ</u>  

    La      4 3   3 +½  

    Ce     4 3   2 +½  

    Pr      4 3   1  +½  

    Nd    4 3   0 +½  

    Pm   4 3  -1   +½  

    Sm   4 3 -2 +½  

The element is samarium, Sm.  

<em>Quantum numbers (5,2,-1,-½)  </em>

<em>n</em> = 5: Principal quantum number = 5.  

<em>l</em> = 2: Element has <em>5d</em> electrons  

We get the following table:  

<u>Element </u><em><u>n</u></em><u>  </u><em><u>l m</u></em><u>ₗ mₛ</u><em><u>  </u></em>

<em>  </em>   Y       5<em> </em>2  2 +½  

    Zr      5 2  1 +½  

    Nb    5 2  0 +½  

    Mo   5 2  -1 +½  

    Tc    5 2  -2 +½  

    Ru   5 2   2  -½  

    Rh   5 2   1   -½  

    Pd   5 2   0  -½  

    Ag   5 2  -1  -½  

The element is silver, Ag.

<em>Note</em>: These assignments assume that there are <em>no exceptions</em> in the Periodic Table.

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*
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