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Lemur [1.5K]
2 years ago
15

Which is a site where sedimentary rocks form? A. deep underground B. forests C. volcanoes D. ancient seas

Chemistry
2 answers:
grin007 [14]2 years ago
7 0
Sedimentary rocks are formed in D. ancient seas because they are formed when layers of sediment (sand, mud, dead organisms, etc) builds up on top of each other and pressure compresses them into rock
Reil [10]2 years ago
3 0
<span>C. volcanoes   
       Hope it Helped</span>
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8). How many moles of oxygen gas must be placed in a 35.0 L container in order
klemol [59]

Answer:

4.1 moles

Explanation:

Applying

PV = nRT................ equation 1

Where P = pressure, V = volume, n = number of moles, R = molar gas constant, T = Temperature.

make n the subject  of the equation

n = PV/RT.............. Equation 2

From the question,

Given: V = 35 L , P = 2.8 atm, T = 15 °C  = (15+273) = 288 K, R = 0.083 L.atm/K.mol

Substitute these values into equation 2

n = (35×2.8)/(0.083×288)

n = 4.1 moles

5 0
2 years ago
Competition occurs when
Katen [24]

Answer:

Competition occurs when <em>(A) two or more organisms need the same resource.</em>

Explanation:

I dont think it could be (B), (C) or (D) because those don't really make sense.

3 0
2 years ago
Which of the following mixture types canNOT be filtered to remove solutes?
iVinArrow [24]
1. A) Colloids only

2. C) M<span>olecules of the dispersion medium colliding with dispered phase particles 

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3 0
2 years ago
Compare the function of a switch in an electric circuit to the function of a water faucet. How are they different?
Sever21 [200]
They both turn something on, and the way they are different is the way they turn it off<span>
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5 0
3 years ago
(C6H6) can be biodegraded by microorganism. if 30 mg of benzene is present, what amount of oxygen required for biodegradation, n
quester [9]

Answer:

36.92 mg of oxygen required for bio-degradation.

Explanation:

5C_6H_6+15O_2\rightarrow 12CO_2+15H_2O

Mass of benzene = 30 mg = 0.03 g (1000 mg = 1 g )

Moles benzene =\frac{0.03 g}{78 g/mol}=0.0003846 mol

According to reaction 5 moles of benzene reacts with 15 moles of oxygen gas.

Then 0.0003846 mol of benzene will react with:

\frac{15}{5}\times 0.0003846 mol=0.0011538 mol of oxygen gas

Mass of 0.0011538 moles of oxygen gas:

0.0011538 mol × 32 g/mol = 0.03692 g = 36.92 mg

36.92 mg of oxygen required for bio-degradation.

4 0
2 years ago
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