Answer:
Step-by-step explanation:
Answer:
63, 64, 65
Step-by-step explanation:
Consecutive integers have a difference of 1 between them
let the 3 integers be n, n + 1 and n + 2 , then their sum equals 192
n + n + 1 + n + 2 = 192
3n + 3 = 192 ( subtract 3 from both sides )
3n = 189 ( divide both sides by 3 )
n = 63 ⇒ n + 1 = 64 and n + 2 = 65
the 3 integers are 63, 64 and 65
The answer is
4 hope it helps
-3x+2y=8
Steps:
1) Add 3x to both sides to get rid of it by the y.
2y=3x+8
2) Divide both sides by 2 to isolate the y.
y= 3/2x + 8/2
3) Simplify (divide 8 by 2)
y= 3/2x+4
Hope this helps!
Answer:
It is a common factor of 9 and 15, so A