Solve for x. Use the quadratic formula. 2 x 2 −9x+8=0 Enter the solutions, in simplified radical form, in the boxes.

Mathematics

2 answers:

Lemur [1.5K]3 years ago

8 0

I apologize if it’s not the right anwser but i got it online ( the anwser)

Mars2501 [29]3 years ago

4 0

Answer:

$\tt x_1=\cfrac{9-\sqrt{17}}{4}; \ \ x_2=\cfrac{9+\sqrt{17}}{4}$

Step-by-step explanation:

$\displaystyle\tt 2x^2-9x+8=0\\\\x=\frac{-bб \sqrt{b^2-4ac}}{2a} \\\\x=\frac{9б\sqrt{(-9)^2-4\cdot2\cdot8}}{2\cdot2} \\\\x=\frac{9б\sqrt{81-64}}{4}\\\\x=\frac{9б\sqrt{17}}{4}\\\\x_1=\frac{9- \sqrt{17}}{4}\\\\x_2=\frac{9+ \sqrt{17}}{4}$

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I need help understanding how to do the problem

notsponge [240]

So.. if you notice the picture below

is really just 3/4 of a cylinder, or, a full cylinder, and then you slice 1/4 off of it
notice the right-angle in your picture at the bottom, is cut at a right-angle, meaning, the cutout is 1/4 of the volume

so $\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h\qquad 
\begin{cases}
r=radius\\
h=height
\end{cases}\qquad \frac{3}{4}\textit{ of that}\implies \cfrac{3}{4}\cdot \pi r^2 h$