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3 years ago

8x-4y=16 -5x-5y=5 Graph the both

Mathematics

2 answers:

Free_Kalibri [48]3 years ago

7 0

When graphing the two equations you have to see what the two equations intersect with which would be (1,-2)

Sergeeva-Olga [200]3 years ago

3 0

Put the equations in slope intercept form in order to graph them(solve for y)

y=2x-4

y= -x-1

Both will be intersecting (1,-2)

You might be interested in

It took James 5h to paint an 8ft by 24ft wall. At this rate, how long would it take him to paint a 12ft by 36ft wall

olasank [31]

8 * 24 feet = 192 sq feet per 5 hours

12* 36 = 432 square feet

432 is 2.25 times the area of 192 square feet

So, it takes 5 * 2.25 = 11.25 hours

7 0

3 years ago

Any mathematics genius around. To solve this question.. am giving the brainliest

Likurg_2 [28]

Well
It is in the form of a/b + b/a = (a sqr + b sqr)ab

Substitute
(Sin sqr theta + cos sqr theta) +2 cos theta + 1. 2 + 2cos theta
———————————————————————— = ————————-
Sin theta(1+cos theta). Sin theta (1 + cos theta)

2(1+ cos theta)/sin theta(1 + cos theta). {1 + cos theta cancelled}
2/sin theta. Hope it helps :}

7 0

2 years ago

What is b?<br> 6/8 = 21/b

padilas [110]

Answer:

b = 28

Step-by-step explanation:

8*21 then 168/6 = 28

4 0

2 years ago

Read 2 more answers

A study was conducted to measure the effectiveness of hypnotism in reducing pain. The measurements are centimeters on a pain sca

blondinia [14]

The confidence interval for mean of the "before-after" differences is $\fbox{(-0.4037,1.8037)}$

Further explanation:

Find the difference between the before pain and the after pain.

Difference = before-after

Kindly refer to the Table for the difference of between the before and after pain.

Sum of difference = $5.6$

Total number of observation = $8$

Mean of difference = $0.7$

Sample standard deviation $s$ = $1.3201$

Level of significance = $5\%$

Formula for confidence interval = $\left( \bar{X} \pm t_{n-1, \frac{\alpha}{2}\%} \frac{s}{\sqrt{n}} \right)$

confidence interval = $\left( 0.7 \pm t_{8-1, \frac{5}{2}\%} \frac{1.3201}{\sqrt{8}} \right)$

confidence interval = $\left( 0.7 \pm t_{7, \frac{5}{2}\%} \frac{1.3201}{\sqrt{8}} \right)$

From the t-table.

The value of $t_{7, \frac{5}{2}\%$ = $2.365$

Confidence interval = $( 0.7 \pm 2.365}\times \frac{1.3201}{\sqrt{8}}) \right)$

Confidence interval = $\left( 0.7 - 2.365}\times \0.4667,0.7 + 2.365}\times \0.4667) \right$

Confidence interval = $(0.7-1.1037,0.7+1.1037)$

Confidence interval = $\fbox{(-0.4037,1.8037)}$

The $95\%$ confidence interval tells us about that $95\%$ chances of the true mean or population mean lies in the interval.

Yes, the hypnotism appear to be effective in reducing pain as confidence interval include includes the positive deviation from the mean.

Learn More:

1. Learn more about equation of circle brainly.com/question/1506955

2. Learn more about line segments brainly.com/question/909890

Answer Details:

Grade: College Statistics

Subject: Mathematics

Chapter: Confidence Interval

Keywords:

Probability, Statistics, Speed dating, Females rating, Confidence interval, t-test, Level of significance , Normal distribution, Central Limit Theorem, t-table, Population mean, Sample mean, Standard deviation, Symmetric, Variance.

7 0

3 years ago

Read 2 more answers

Someone please help !! I don’t know what I’m doing with this !!

dimulka [17.4K]

Answer:

a) d(sinh(f(x)))/dx = cosh(f(x))·df(x)/dx

b) d(cosh(f(x))/dx = sinh(f(x))·df(x)/dx

c) d(tanh(f(x))/dx = sech(f(x))²·df(x)/dx

d) d(sech(4x+2))/dx = -4sech(4x+2)tanh(4x+2)

Step-by-step explanation:

To do these, you need to be familiar with the derivatives of hyperbolic functions and with the chain rule.

The chain rule tells you that ...

(f(g(x)))' = f'(g(x))g'(x) . . . . where the prime indicates the derivative

The attached table tells you the derivatives of the hyperbolic trig functions, so you can answer the first three easily.

a) sinh(u)' = sinh'(u)·u' = cosh(u)·u'

For u = f(x), this becomes ...

sinh(f(x))' = cosh(f(x))·f'(x)

b) After the same pattern as in (a), ...

cosh(f(x))' = sinh(f(x))·f'(x)

c) Similarly, ...

tanh(f(x))' = sech(f(x))²·f'(x)

d) For this one, we need the derivative of sech(x) = 1/cosh(x). The power rule applies, so we have ...

sech(x)' = (cosh(x)^-1)' = -1/cosh(x)²·cosh'(x) = -sinh(x)/cosh(x)²

sech(x)' = -sech(x)·tanh(x) . . . . . basic formula

Now, we will use this as above.

sech(4x+2)' = -sech(4x+2)·tanh(4x+2)·(4x+2)'

sech(4x+2)' = -4·sech(4x+2)·tanh(4x+2)

_____

Here we have used the "prime" notation rather than d( )/dx to indicate the derivative with respect to x. You need to use the notation expected by your grader.

<em>Additional comment on notation</em>

Some places we have used fun(x)' and others we have used fun'(x). These are essentially interchangeable when the argument is x. When the argument is some function of x, we mean fun(u)' to be the derivative of the function after it has been evaluated with u as an argument. We mean fun'(u) to be the derivative of the function, which is then evaluated with u as an argument. This distinction makes it possible to write the chain rule as ...

f(u)' = f'(u)u'

without getting involved in infinite recursion.

7 0

2 years ago