Answer:
Rate of change for the linear relationship modeled is 
Step-by-step explanation:
As the there is a linear relationship in the points, so all these points will be on a single straight line. Hence the slope will be same throughout all the points.
We know that, the slope of the line joining (x₁, y₁) and (x₂, y₂) is,
Putting the points as (-1, 10) and (1, 9), we get
Rate of change is the slope of the line joining all these points.
Answer:
26.25
Step-by-step explanation:
y = 8.75(3)
y = 26.25
Answer: A
Step-by-step explanation:
The first thing we need to do is to make sure our equation is in standard form. The given equation is not in standard form.
3x²-2x=0
Now that the equation is in standard form, we can find our A, B, C to see which quadratic equation is correct.
A=3
B=-2
C=0
We can automatically eliminate D because the first value is -3 when it is supposed to be -(-2). Also, the denominator is supposed to be 2a. We know that A=3. The denominator should be 2(3), not 2(-2).
Next, we can eliminate B and C. For the 4ac, we know it has to be 4(3)(0) because A=3 and C=0. B and C have given 4(3)(2) and 4(3)(1), respectively. This does not match A=3 and C=0.
Therefore, A is the correct answer.
Answer:
Compound interest = Rs 1,575 (Approx.)
Step-by-step explanation:
Given:
Amount invested = R.s 6,500
Rate of interest = 7.5% per annum
Number of year = 3 year
Find:
Amount of compound interest
Computation:
Compound interest = P[(1+r)ⁿ - 1]
Compound interest = 6500[(1+7.5%)³ - 1]
Compound interest = 6500[(1+0.075)³ - 1]
Compound interest = 6500[(1.075)³ - 1]
Compound interest = 6500[1.2423 - 1]
Compound interest = 6500[0.2423]
Compound interest = 1574.95
Compound interest = Rs 1,575 (Approx.)
Since there were 9 feet of ribbon and Jim uses 1/3 we are going to do 9/1 * 1/3 and get 3 Jim makes 3 ribbons.
