Given:
The function, f(x) = -2x^2 + x + 5
Quadratic equation: 0 = -2x^2 + x +5
where a = -2
b = 1
c = 5
The discriminate b^2 - 4ac = 41
To solve for the zeros of the quadratic function, use this formula:
x = ( -b +-√ (b^2 - 4ac) ) / 2a
x = ( 1 + √41 ) / 4 or 1.85
x = ( 1 - √41 ) / 4 or -1.35
Therefore, the zeros of the quadratic equation are 1.85 and -1.35.
Answer:
6) The median is 80
7) The 1st quartile is 60
8) The 3rd quartile is 100
9) The minimum value is 40
10) The maximum value is 110
Step-by-step explanation:
Line up where the points are
The correct answer is B) y + 9 = 2(x - 1)
In order to find this, simply take the point and the slope and plug into the base form of point-slope form.
y - y1 = m(x - x1)
Use the slope for m and the point for (x1, y1)
y + 9 = 2(x - 1)
Answer:
D
Step-by-step explanation:
-3 1/8 - 2 1/2 is the same as -3 1/2 + -2 1/2
Answer: From what you wrote the I think the ball is drop
At time 0 you are 7 meters above ground
You basically just need to solve for
1.5 =7t-4.9t^2
by rearrange the equation you get
4.9t^2-7t+1.5=0
by using Quadratic Formula
t=1.166s
