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yaroslaw [1]
3 years ago
10

The set of ordered pairs in the table below can be described as which of the following?

Mathematics
1 answer:
skad [1K]3 years ago
6 0
<span>C. both a relation and function</span>
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Wich values of a, b, c represent the answer in simplest form 7/9 ÷4/9= a b/c
ladessa [460]

Answer:

74=ab/c

Step-by-step explanation:

a=7c/4b

b=7c/4a

c=4ab/7

7 0
3 years ago
Which expression is equivalent to the given expression?
Studentka2010 [4]
Which expression is equivalent to the given expression?

15(12-x)

A. 15*12-x


hope this help
4 0
3 years ago
F(x)=x2 + 2x2-x-2<br><br><br><br><br><br><br><br> Help please
mel-nik [20]
The answer is d. Hopefully you get it right
6 0
3 years ago
Two forces with magnitudes of 100 and 50 pounds act on an object at angles of 50° and 160°, respectively. Find the direction and
shusha [124]
Forces in direction x:
 
fx1 = 100 * cos (50) = 64.28
 fx2 = 50 * cos (160) = - 46.99
 The resultant is:
 fx = fx1 + fx2 = 17.29

 Forces in direction y:
 
fy1 = 100 * sine (50) = 76.60
 fy2 = 50 * sine (160) = 17.10
 The resultant is:
 fy = fy1 + fy2 = 93.70
 The magnitude of the resulting force is:
 
f = root (fx ^ 2 + fy ^ 2)
 f = root ((17.29) ^ 2 + (93.70) ^ 2)
 f = 95.28
 The angle is:
 
theta = atan (fy / fx)
 theta = atan (93.70 / 17.29)
 theta = 79.55 degrees
 Answer:
 
The direction and magnitude of the resultant force are:
 
f = 95.28 pounds at theta = 79.55 degrees
6 0
3 years ago
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
maxonik [38]

Answer:

5.0 ft-lbf

Step-by-step explanation:

The force is

F = \dfrac{9}{6^x}

This force is not a constant force. For a non-constant force, the work done, <em>W</em>, is

W = \int\limits^{x_2}_{x_1} {F(x)} \, dx

with x_1 and x_2 the initial and final displacements respectively.

From the question, x_1  =0 and x_2 = 12.

Then

W = \int\limits^{12}_0 {\dfrac{9}{6^x}} \, dx

Evaluating the indefinite integral,

\int\limits \dfrac{9}{6^x} \, dx  =9 \int\limits\!\left(\frac{1}{6}\right)^x \, dx

From the rules of integration,

\int\limits a^x\, dx = \dfrac{a^x}{\ln a}

9 \int\limits \left(\frac{1}{6}\right)^x \, dx = 9\times\dfrac{(1/6)^x}{\ln(1/6)} = -5.0229\left(\dfrac{1}{6}\right)^x

Returning the limits,

\left.-5.0229\left(\dfrac{1}{6}\right)^x\right|^{12}_0 = -5.0229(0.1667^{12} - 0.1667^0) = 5.0229 \approx 5.0 \text{ ft-lbf}

4 0
3 years ago
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