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VashaNatasha [74]
3 years ago
14

Malwar is the short form for malicious software and used to refer​

Computers and Technology
1 answer:
bearhunter [10]3 years ago
7 0

Answer:

Malware is the shortened form of malicious software. Malware is an umbrella term used to refer to a variety of forms of hostile or intrusive software including Ransom wares, Computer Viruses, Worms, Trojan Horses, Spyware, Adware, Scareware etc.

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You implement basic version control and go through the phase of creating a local repository. Initiate the commands to set up tha
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Version control is the foundation of DevOps. Gain speed with Helix Core. Get the version control tools you need. Try today. Modern Collaboration. Increase Visibility.
3 0
3 years ago
Sue conducted an experiment to determine which paper towel is the most absorbent among three different brands. She decides to pr
Triss [41]

Answer:

Its C

Explanation:

On Edg

7 0
3 years ago
The right headlight does not function on either high or low beam. Technician A says this could be caused by an open ground on th
dangina [55]

Answer: Technician A is correct.

Explanation: An open ground on the right may be the reason the headlight is not functioning on low or high beam. Most electrical circuit related problems in automotive are caused by open ground.

A ground should be clean, tight and free of corrosion and also making good metal to metal contact.

A ground is an electrical circuit system or connection in an automotive.

A dimmer switch on the other hand is a device that controls the vehicle's headlight functions. If the headlight does not function on high or low on the right. It can't be a dimmer switch, hence it may be ground problem.

4 0
3 years ago
Write a method so that the main() code below can be replaced by the simpler code that calls method mphAndMinutesToMiles(). Origi
defon

ANSWER

The JAVA program after simplification is as below.

import java.util.Scanner;

public class CalcMiles {

   

   // variables declaration

   static double milesPerHour;

   static double minutesTraveled;      

   static double hoursTraveled;

   static double milesTraveled;

   

   // method declared static

   public static void mphAndMinutesToMiles(double speed, double mins)

   {

       // computations to calculate distance travelled

       hoursTraveled = mins / 60.0;

       milesTraveled = hoursTraveled * speed;

       

       // result displayed on the screen  

     System.out.println("Miles: " + milesTraveled);

   }

   

   // Scanner object created inside main()

   // user input taken inside main()

   public static void main(String [] args)

   {

       Scanner scnr = new Scanner(System.in);

       System.out.println("Enter miles travelled per hour ");

       milesPerHour = scnr.nextDouble();

       System.out.println("Enter minutes required to travel ");

       minutesTraveled = scnr.nextDouble();

       

       mphAndMinutesToMiles(milesPerHour, minutesTraveled);

       

   }

}

OUTPUT

Enter miles travelled per hour  

2.3

Enter minutes required to travel  

1234

Miles: 47.30333333333333

EXPLANATION

The program is simplified as explained below.

1. User input is taken using the object of Scanner class.

2. This object of Scanner class can only be created inside main() method hence, user input can only be taken inside main().

3. The code to calculate the result is separated in another method, mphAndMinutesToMiles(). This method is declared with return type void since no value is returned.

4. After user input is taken in main() for miles travelled per hour and minutes required to travel, these values are passed as parameters to the mphAndMinutesToMiles() method.

5. These parameters are used in calculation part. The total miles travelled in total hours (obtained from minutes), is calculated. The code to display the result is added to this method.

6. Inside the main method, only the code to create Scanner object, code to take user input for two variables and code to call the mphAndMinutesToMiles() is included.

7. The variables are declared as static and declared at class level.

8. No variable is declared inside any of the two methods.

5 0
3 years ago
Read 2 more answers
Given a vector of students, the function FinalAvg is supposed to return the average final exam score across all the students in
alexandr1967 [171]

Answer:

The C++ code is given below with appropriate comments

Explanation:

#define CATCH_CONFIG_MAIN //This tells Catch to provide a main()

#include"catch.hpp" //Header for Catch Framework

double FinalAvg( vector <int> students) // Function to calculate average.

{

double sum =0;

int i;

for( i=0;i<v.size();i++) sum+= v[i];

return v.empty() ? 0.0 : (double(sum)/ v.size());

}

vector<int> func(int argvq[ ]) // This function is made because we can not provide vector in command line argument that's why we used array which is then conerted into vector.

{

vector<int> v;

int j;

int l= sizeof(argvq)/sizeof(argvq[0]);

for(j=0;j<l;j++)

v.push_back(argq[j]);

return v;

}

TEST_CASE(" Final Average marks are computed","[func]") // TEST_ CASE macro to take one or more arguments

{

REQUIRE( func(9,5,-7) == 7); // We write our individual test assertions using the REQUIRE macro.

REQUIRE(func(2,4,6,-2) ==4);

}

Explanation Using different IDE:

#include<bits/stdc++.h>

using namespace std;

double FinalAvg(vector<int> students)

{

double sum=0;

for(int i=0;i<v.size();i++) sum+= v[i];

return v.empty() ? 0.0 : (double(sum)/v.size());

}

int main()

{

vector<int> v;

int i;

while(cin>>i&&i>0) v.push_back(i);

cout<<Final Avg(v);

return 0;

}

8 0
3 years ago
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