The student’s suggestion who provides enough evidence to be able to determine the value of each resistor is student D.
<h3>What is current?</h3>
The current is the stream of charges which flow inside the conductors when connected across the end of voltage.
For the given set of parallel resistors, we need to find the resistance of each resistor.
From the Ohm's law, V =IR
R = V/I
Resistance value depends upon the voltage difference across the resistor and the current flowing through that resistance.
Thus, the student D gives enough evidence to find resistance of the circuit is
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Answer:
v = 7.32 m/s
Explanation:
The potential energy will convert to kinetic energy
½Iω² + ½mv² = mgh
Iω² + mv² = 2mgh
(½mR²)(v/R)² + mv² = 2mgh
½mv² + mv² = 2mgh
½v² + v² = 2gh
3v²/2 = 2gh
v² = 4gh/3
v² = 4(9.81)(4.10)/3
v² = 53.628
v = 7.323114...
v = 7.32 m/s
Using Kepler's third law which is defined as the square of the average distance is directly proportional to the cube of the period. It is expressed as P^2 = a^3, Given that the a = average distance is given, the period would be much easier to compute. P = sqrt(27^3) = 140
Answer:
The current through the wire is equal to 0.8 A.
Explanation:
Given that,
The length of a copper wire = 2 m
Potential difference = 24 mV
The current through the wire is 0.40 A.
The new potential difference is 48 mV.
We need to find the current through the wire.
As the potential difference is doubled for second wire. So the new current will be :
I' = 2I
= 2 × 0.4
= 0.80 A
So, the current through the wire is equal to 0.8 A.
use consevation of linear momentum
- m1v1+m2v2=(M1+M2)V3
- 281(2.82)+209(-1.72)=(209+281)V2
- 792.42-359.48=490v3
- 432.9=490v3
- V3=0.88m/s
