Question

A car is traveling due north at 23.6 m>s.

Answer 1

A car is traveling due north at 23.6 m>s.

Find the velocity of the car after 7.10 s if its

acceleration is

The acceleration is known to be: a(t) = 1.7 m/s2.

We must integrate over time to obtain the velocity function, and the results are:

v(t) = (1.7m/s^2)

*t + v0

If we suppose that we begin at 23.6 m/s, then the initial velocity is: v0 = 23.6 m/s, where v0 is the beginning velocity.

The velocity formula is then: v(t) = (1.7m/s2).

*t + 23.6 m/s

We now seek to determine the value of t such that v(t) = 27.8 m/s.

Consequently, v(t) = 27.8 m/s = (1.7 m/s2)

*t + 23.6 m/s = (1.7 m/s2) 27.8 m/s - 23.6 m/s

t = 2.5 seconds when *t 4.2 m/s = (1.7 m/s/2)

At such acceleration, 2.5 seconds are required.

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