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Sergeu [11.5K]
3 years ago
11

What will be the acceleration of a 40-kilogram object that is pushed with a net force of 80 newtons?

Physics
1 answer:
ratelena [41]3 years ago
4 0
= 80 N/40 kg
= 2 m/s 2
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Why is atomaspheric pressure greater at the surface on Earth
andrew-mc [135]
Hello!

Because as you get closer to the surface of the earth, the more air that is on top of you. At the top of the atmosphere, there is less air, and everything is a vacuum, where you have no weight. When you get close to the earth, the weight of the air builds until it when you're at the very lowest point of the earths surface, all the air in the atmosphere above you is pressing down.

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5 0
3 years ago
Read 2 more answers
A speed skater moving across frictionless ice at 9.2 m/s hits a 5.0 m wide patch of rough ice. She slows steadily, then continue
enot [183]

Answer:

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

Explanation:

The distance travelled on the rough ice is equal to the width of the rough ice.

distance d = 5.0 m

Initial speed u = 9.2 m/s

Final speed v = 5.8 m/s

The time taken to move through the rough ice can be calculated using the equation of motion;

d = 0.5(u+v)t

time t = 2d/(u+v)

Substituting the given values;

t = 2(5)/(9.2+5.8)

t = 2/3 = 0.66667 second

The acceleration is the change in velocity per unit time;

acceleration a = ∆v/t

a = (v-u)/t

Substituting the values;

a = (5.8-9.2)/0.66667

a = -5.099974500127

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

7 0
3 years ago
How much current is in a circuit that includes a 9-volt battery with a resistance of 3
Darya [45]
Just remember
Voltage = current times resistance

current = voltage over resistance

Current = 9/3 = 3
7 0
3 years ago
If a current is two amps and the resistance is 3 ohms, how much voltage was needed?
Hunter-Best [27]

Answer:

6 V

Explanation:

We can solve the problem by using Ohm's law:

V=RI

where

V is the voltage in the circuit

R is the resistance

I is the current

In this problem, we know the current, I=2 A, and the resistance, R=3 \Omega, therefore we can find the voltage in the circuit:

V=RI=(3 \Omega )(2 A)=6 V

7 0
2 years ago
Two poles are connected by a wire that is also connected to the ground. The first pole is 20ft tall and the second pole is 10ft
Natasha2012 [34]

Answer: 31.6ft

Explanation:

Check the attachment for the diagram.

According to the right angle triangle AEC, we will use Pythagoras theorem to get |AC|. Note that |AE| = |AB| - |CD|

that is 20ft - 10ft = 10ft

According to the theorem, the square of the sum of the adjacent side and the opposite side is equal to the square of the hypotenuse.

|AE|^2 + |EC|^2 = |AC|^2

10^2 + 30^2 = |AC|^2

100 + 900 = |AC|^2

|AC| = √1000

|AC| = 31.6ft

Therefore, the wire should be anchored 31.6ft to the ground to minimize the amount of wire needed.

6 0
3 years ago
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