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3 years ago

An object moves 2.5 m. This is an example of a _______. Question 3 options: direction distance velocity speed

Physics

2 answers:

Hitman42 [59]3 years ago

5 0

Distance, since distance represents how far something has travelled, which would be in our case 2.5m.

Mila [183]3 years ago

5 0

An object moves 2.5 m. This is an example of a distance

Answer: Option B

Explanation:

In the above example, the direction of the object in which it moved is not given here. Hence Option A is invalid. Velocity and speed are similar as they indicate the distance travelled by the object with respect to time.

The distance travelled by the object with respect to time is not given in the example and so Option C and D are invalid. So distance is the best option.

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When the number of electrons striking the anode of an x-ray tube is increased, the ____ of the emitted X-Ray increases.

Sphinxa [80]

When the number of electrons striking the anode of an X-ray tube is increased, the density of the emitted x-ray increases

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3 years ago

A body is projected upward at an angle of 30 degree to the horizontal at an initial speed of 200ms-.In how many seconds will it

Crazy boy [7]

Answer:

20.41 s

3534.80 m

Explanation:

In how many seconds will it reach the ground?

We are given the initial velocity of the body, which is 200 m/s at a 30° angle.

We know the acceleration in the vertical direction is -9.8 m/s², assuming that the upwards/right direction is positive and the downwards/left direction is negative.

Since we are using acceleration in the y-direction, let's use the vertical component of the initial velocity.

200 · sin(30) m/s

Let's use the fact that at the top of its trajectory, the body will have a final velocity of 0 m/s.

Now we have one missing variable that we are trying to solve for: time t.

Find the constant acceleration equation that contains v₀, v, a, and t.

v = v₀ + at

Substitute known values into the equation.

0 = 200 · sin(30) + (-9.8)t
-200 · sin(30) = -9.8t
t = 10.20408163

Recall that this is only half of the body's trajectory, so we need to double the time value we found to find the total time the body is in the air.

2t = 20.40816327

The body will reach the ground in 20.41 seconds.

How far from the point of projection would it strike?

We want to find the displacement in the x-direction for the body.

Let's find the constant acceleration equation that contains time t, that we just found, and displacement (Δx).

Δx = v₀t + 1/2at²

Substitute known values into the equation. Remember that we want to use the horizontal component of the initial velocity and that the acceleration in the x-direction is 0 m/s².

Δx = (200 · cos(30) · 20.40816327) + 1/2(0)(20.40816327)²
Δx = 3534.797567

The body will strike 3534.80 m from the point of projection.

4 0

2 years ago

In this problem, you will practice applying this formula to several situations involving angular acceleration. in all of these s

MatroZZZ [7]

A- 2*[(m1 - m2)/(m1 + m2)]*g/L The rotation is in the counterclockwise direction and the angular acceleration is positive. B- 2*[(m1 - m2)/(m1+ m2 +mbar/3)]*g/L The rotation is in the counterclockwise direction and the angular acceleration is positive.

6 0

3 years ago

Suppose your grocery cart is moving at a constant momentum in a straight line down the aisle of a store, without friction. How w

Strike441 [17]

Answer:

It will increase

Explanation:

The kinetic energy is the energy possessed by a moving object and is given by:

KE = $1/2 mv^2$

where m = mass of the object and v = velocity of the object.

It does means that the more the mass of an object in motion, the more the kinetic energy of the object if there are no opposing force such as friction. Also, the more the kinetic energy of the object, the more the speed of that object.

Hence, as the weight of the cart increases by addition of groceries, the kinetic energy increases and the speed also increases as it moves along the frictionless surface.

7 0

3 years ago

A sample of gas occupies a volume of 57.8 mL 57.8 mL . As it expands, it does 110.8 J 110.8 J of work on its surroundings at a c

Vinvika [58]

Answer: The final volume of the gas is 1.12 L

Explanation:

W = work done on or by the system

w = work done by the system = $P\Delta V$