Answer:
7/20
Step-by-step explanation:
add the probabilities together and minus it by the LCM which is 20
Step-by-step explanation:
Note: Question does not indicate if probability required is for weight to exceed or below 3000 lbs. So choose appropriate answer accordingly (near the end)
Using the usual notations and formulas,
mean, mu = 3550
standard deviation, sigma = 870
Observed value, X = 3000
We calculate
Z = (X-mu)/sigma = (3000-3550)/870 = -0.6321839
Probability of weight below 3000 lbs
= P(X<3000) = P(z<Z) = P(z<-0.6321839) = 0.2636334
Answer:
Probability that a car randomly selected is less than 3000
= P(X<3000) = 0.2636 (to 4 decimals)
Probability that a car randomly selected is greater than 3000
= 1 - P(X<3000) = 1 - 0.2636 (to 4 decimals) = 0.7364 (to 4 decimals)
Answer:
Step-by-step explanation:
m<1 = m<2
8y - 6 = 7y
8y - 7y = 6
y = 6°
m<2 = 7y = 7(6) = 42°
Answer:
x = 4
Step-by-step explanation:
change the signs on both sides of the equation
7-4x= - 9
move constant to the right side and change its sign
- 4x = - 9 - 7
-4x= - 16
divide both sides of the equation by -4
x = 4
Y = 2x - 10
y = 4x - 8
2x - 10 = 4x - 8
2x - 4x = -8 + 10
-2x = 2
x = -2/2
x = -1
y = 4x - 8
y = 4(-1) - 8
y = -4 - 8
y = -12
solution is (-1,-12)