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Viktor [21]
3 years ago
8

The Better Baby Buggy Co. has just come out with a new model, the Turbo. The market research department predicts that the demand

equation for Turbos is given by 
q = −4p + 544,

 where q is the number of buggies the company can sell in a month if the price is $p per buggy. At what price should it sell the buggies to get the largest revenue?
Mathematics
1 answer:
dlinn [17]3 years ago
8 0

Answer:

$68

Step-by-step explanation:

We have been given the demand equation for Turbos as q=-4p+544, where q is the number of buggies the company can sell in a month if the price is $p per buggy.

Let us find revenue function by multiplying price of p units by demand function as:

Revenue function: pq=p(-4p+544)

pq=-4p^2+544p

Since revenue function is a downward opening parabola, so its maximum point will be vertex.

Let us find x-coordinate of vertex using formula \frac{-b}{2a}.

\frac{-b}{2a}=\frac{-544}{2\times -4}

\frac{-b}{2a}=\frac{-544}{-8}

\frac{-b}{2a}=68

The maximum revenue would be the y-coordinate of vertex.

Let us substitute x=68 in revenue formula.

pq=-4(68)^2+544(68)

pq=-4*4624+544(68)

pq=-18496+36992

pq=18496

Therefore, the company should sell each buggy for $68 to get the maximum revenue of $18,496.

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