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aniked [119]
4 years ago
10

A line spectrum is produced when an electron moves from one energy level

Physics
1 answer:
dolphi86 [110]4 years ago
4 0

Answer:

Explanation:

A line spectrum in form of emission line is usually produced when an electron moves from higher energy level to lower energy orbit. During this process the electron loses certain amount of energy called photons with specific amount. The energy of the photon = the difference in energy of the orbits.

DE = E2-E1 where E2 electron with higher energy orbit.

It is possible for the electron to reach ground state in one jump or stop at one energy level temporarily but it cannot stop between energy levels.

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Here we have a time-position graph with some points marked on it, and we want to analyze some points in it.

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In this case, the point is D.

2) Remember that the graph evolves to the right, so, if at any point, the right side is above the left side, then at that particular point the object is moving to the left (negative x-axis)

In this case, the points are:

C, D, and E.

3) The object speeds up when the curvature of the curve changes and the slope increases, for example, from B onwards, the speed increases.

Then at point C the speed is increasing.

4) Opposite to what we said before, if the slope decreases then the object is slowing down.

In this case we can see that the slope decreases after A and after E.

5) When the object is turning around?

This is easy, we can see that the object goes to the right (positive x-axis) until it reaches B and then goes back, then at point B the object turns around.

If you want to learn more, you can read:

brainly.com/question/11290689

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3 years ago
The sudden drain of a magma chamber can form a caldera.<br><br> True<br><br> False
Sladkaya [172]
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What is the weight in newtons of a 10 kg mass on the earth's<br> surface?
juin [17]

Answer:

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White light (light containing all frequencies of light in the visible spectrum) passes through a diffraction grating with 1300 l
lara31 [8.8K]

Answer:

The distance between the 1st order blue fringe and the 1st order red fringe is 6.5 cm.

Explanation:

Given that,

Diffraction grating =1300 lines/cm

Distance of screen = 2 m

Order number = 1

We need to calculate the distance between the 1st order blue fringe and the 1st order red fringe

Using formula of distance

For first order red fringe

d\sin\theta=m\lambda

d\times\dfrac{y}{l}=m\times\lambda

y_{r}=\dfrac{m\times\lambda l}{d}

y_{r}=\dfrac{1\times700\times10^{-9}\times2}{\dfrac{1}{1300}\times10^{-2}}

y_{r}=0.182\ m

For first order blue fringe

y_{b}=\dfrac{1\times450\times10^{-9}\times2}{\dfrac{1}{1300}\times10^{-2}}

y_{b}=0.117\ m

We need to calculate the distance between blue fringe and red fringe

\Delta y=y_{r}-y_{b}

\Delta y=0.182-0.117

\Delta y=0.065\ m=6.5 cm

Hence, The distance between the 1st order blue fringe and the 1st order red fringe is 6.5 cm.

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