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3 years ago

WILL GIVE BRAINLIEST!!!

Physics

1 answer:

Gemiola [76]3 years ago

3 0

Answer:

1/Re=1/R1 +1/R2= 2x1/R1=2/R1=2/R2=2/50=1/25

1/Re=1/25, so the answer is Re= 25

the answer is A. 25.0

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How can I act more like Runa from Kakegurui?

igomit [66]

Answer:

LOVE HER, and just study her, and sometimes just pause and try and act like that, or watch the backstory and go through everything they went through.

Explanation:

Hope this helps

4 0

3 years ago

Read 2 more answers

Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 3.00 m above

statuscvo [17]

Answer: The gravitational acceleration near the surface of this planet is 9.056 m/s^2

Explanation:

When you drop an object, the only acceleration acting on the object is the gravitational acceleration, so we can writhe the acceleration of the wrench as

a(t) = -g

where the minus sign is because the wrench will move downwards.

for the velocity of the object, we integrate over time and get:

v(t) = -g*t + v0

where v0 is the initial velocity, in this case is 0, because the wrench is droped.

integrating again, we will get the position of the wrench:

p(t) = -(g/2)*t^2 + p0

where p0 is the initial position, in this case is 3m above the ground.

p(t) = -(g/2)*t^2 + 3m

now, afther 0.814seconds the wrench hits the ground, so we have:

p(0.814 s) = 0 = -(g/2)*(0.814s)^2 + 3m

now we need to solve this for g.

-(g/2)*(0.814s)^2 + 3m = 0

(g/2)*(0.814s)^2 = 3m

(g/2) = 3m/*(0.814s)^2 = 4.528m/s^2

g = 2*4.528m/s^2 = 9.056 m/s^2

6 0

3 years ago

Vector B has x, y, and z components 4, 6, and 3, respectively.

nalin [4]

Bbbbbbbbbbbbbb gygffdd

8 0

3 years ago

A 5000-lb wrecking ball hangs from a 50-ft cable of density 10 lb/ft attached to a crane. Calculate the work done if the crane l

aniked [119]

Answer:

total work is = 52450 J

Explanation:

given data

mass = 5000-lb

density = 10 lb/ft

height = 50 ft

solution

as we will treat here cable and ball are separate

and

here work need to lift cable is

w = (10Δy )(9.8 y ) j

and

now summing all segment of cable

so passing limit Δy to 0

so total work need

= $\int\limits^{10}_0 {98y} \, dy$

= $[49 y^2]^{50}_0$

= 2450J

so lifting 5000 lb wrcking 50 m required additional 5000 + 2450

so total work is = 52450 J

3 0

3 years ago

What is the strength of the electric field in a region where the electric potential is constant?

Roman55 [17]

Answer:

Where the electric potential is constant, the strength of the electric field is zero.

Explanation:

As a test charge moves in a given direction, the rate of change of the electric potential of the charge gives the potential gradient whose negative value is the same as the value of the electric field. In other words, the negative of the slope or gradient of electric potential (V) in a direction, say x, gives the electric field (Eₓ) in that direction. i.e

Eₓ = - dV / dx ----------(i)

From equation (i) above, if electric potential (V) is constant, then the differential (which is the electric field) gives zero.

<em>Therefore, a constant electric potential means that electric field is zero.</em>

4 0

3 years ago