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allsm [11]
3 years ago
13

What is the weight in newtons of a 10 kg mass on the earth's surface?

Physics
2 answers:
juin [17]3 years ago
5 0

Answer:

98 kg

Mass is given as 10 kg. Therefore, Weight = 10 kg * 9.8 m/s^2. Weight = 98 kg.m/s^2. = 98 Newtons.

Explanation:

plz mark me brainleast

GuDViN [60]3 years ago
4 0

The weight in newtons of a 10 kg mass on the earth's  surface is 98 N.

<u>Explanation:</u>

Every object on the Earth experiences an acceleration of 9.8 m/s^2 due to gravity. From the given,

Mass of the object = 10 kg

To calculate the weight of the object we have to multiply the given mass of the object by the acceleration due to gravity.

i.e. Weight= Mass\times Acceleration \ due \ to \ gravity

Acceleration due to gravity = 9.8 m/s^2

On substituting the values,

Weight = 10 kg\times 9.8 m/s^2

(1 N = 1 kg. m/s^2)

\bold{\Rightarrow 98 \ kg.m/s^2\Rightarrow 98 N}

Weight = 98 N

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Read 2 more answers
Two particles are moving with positions given by x= 4t^2−2t and x= 6t^3+8t respectively.
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Acceleration is the second derivative of position.  The acceleration of the first particle is:

x = 4t² − 2t

v = 8t − 2

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The acceleration of the second particle is:

x = 6t³ + 8t

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The first particle has uniform acceleration.

<em>b)Which one is likely to come to rest at some time during its motion?</em>

The particles come to rest when v = 0.  The first particle's velocity has a real zero at t = 4.  The second particle's velocity has only imaginary zeros, meaning v is never 0.

6 0
3 years ago
Assuming a roughly spherical shape and a density of 4000 kg/m3, estimate the diameter of an asteroid having the average mass of
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Explanation:

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Density of asteroid, \rho=4000\ kg/m^3

Mass of asteroid, m=10^{17}\ kg

We need to find the diameter of the asteroid. The formula of density is given by:

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V is the volume of spherical shaped asteroid, V=\dfrac{4}{3}\pi r^3

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Hence, this is the required solution.

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