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Luba_88 [7]
3 years ago
15

1) At which lettered point or points is the object moving the fastest?

Physics
1 answer:
emmainna [20.7K]3 years ago
8 0

Here we have a time-position graph with some points marked on it, and we want to analyze some points in it.

1) The object is moving the fastest in the point where the slope of the curve is the largest.

In this case, the point is D.

2) Remember that the graph evolves to the right, so, if at any point, the right side is above the left side, then at that particular point the object is moving to the left (negative x-axis)

In this case, the points are:

C, D, and E.

3) The object speeds up when the curvature of the curve changes and the slope increases, for example, from B onwards, the speed increases.

Then at point C the speed is increasing.

4) Opposite to what we said before, if the slope decreases then the object is slowing down.

In this case we can see that the slope decreases after A and after E.

5) When the object is turning around?

This is easy, we can see that the object goes to the right (positive x-axis) until it reaches B and then goes back, then at point B the object turns around.

If you want to learn more, you can read:

brainly.com/question/11290689

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Calculate the ph of hydronium ions in a 0.000 01 M solution of the strong acid HI.
quester [9]

Answer:

D. 5

Explanation:

\mathbf{pH=-log_{10}[H^{+}]}

The above formula is used to find pH of any solution. For that you require the concentration of \textrm{H}^{+} or hydronium ion (\textrm{H}_{3}\textrm{O}^{+}) in the solution. Concentration should be in molarity (M) to get the pH.

The concentration of \textrm{H}^{+} ion is given as 0.00001 M or 10^{-5} M.

Substituting the value of \textrm{H}^{+} ion in the formula:

\textrm{pH}=- \textrm{log}_{10}[10^{-5}]

\textrm{pH}=-(-5)\textrm{log}_{10}[10]

\textrm{pH}=-(-5)(1)

\therefore\mathbf{pH=5}

(NOTE : Some logarithmic properties

\mathbf{log_{b}(b)=1}\\ \mathbf{log_{b}(a^{c})=c \cdot log_{b}(a)}

here 'b' is called the base of log and '\mathbf{a^{c}}' is called dthe argument of log. In the solution the base is '10' and the argument is \mathbf{H^{+}})

3 0
3 years ago
An atom of the element chromium has an atomic number of 24 and a mass number of 52. How many electrons are in an uncharged atom
zubka84 [21]

<span>Chromium is represented by the element Cr with an atomic number of 24 and a molar mass of 52 gram per mole. The number of protons in the Chromium atom is the atomic number, so it has 24 protons. And the protons of chromium atom is equal to the number of electrons, so 24 electrons.</span>

4 0
3 years ago
Read 2 more answers
The pressure inside a champagne bottle can be quite high and can launch a cork explosively. Suppose you open a bottle at sea lev
valina [46]

Answer:

Explanation:

Given that,

The absolute pressure inside the champagne is 6 times atmospheric pressure

Atmospheric pressure is 101,325 N/m²

So, the absolute pressure in the champagne is

P_abs = 6 × P_atm

P_abs = 6 × 101,325

P_abs = 607,950 N/m²

If the cork of the champagne has a mass of

M = 7.5g

M = 7.5 / 1000 = 0.0075 kg

The diameter of the cork is 18mm, It is no possible for the diameter to be 18m, so I assumed it is 18mm

d = 18mm = 0.018m

The area of the circle will be

Area = πd² / 4

Area = π × 0.018² / 4

Area = 2.545 × 10^-4 m²

We know that,

Pressure = Force / Area

Then,

Force = Pressure × Area

Force = 607,950 × 2.545 × 10^-4

Force = 154.723 N

Then, from newton second law,

F = ma

a = F / m

a = 154.723 / 0.0075

a = 20629.77 m/s²

a ≈ 20,630 m/s²

The acceleration of the cork is 20,630 m/s²

4 0
4 years ago
When compared to others, how is a greater velocity represented on a motion map?
Rina8888 [55]

Explanation:

At each position, the object's velocity is represented by a vector. If the car were traveling at greater velocity, the strobe photo might look like this: The corresponding motion map has the points spaced farther apart, and the velocity vectors are longer, implying that the car is moving faster.

3 0
3 years ago
Read 2 more answers
What temperature must a gas initially at 10 °c be brought to for the pressure to triple?
VMariaS [17]
We can obtain the answer easily if we assume the gas here is an ideal gas. We can use t he expression:

PV = nRT

we set nR/V = k
P/T = k

P1/T1 = P2/T2

when P2 = 3P1

P1/10 = 3P1/T2
T2 = 30 degrees Celsius
5 0
3 years ago
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