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jonny [76]
3 years ago
10

The specific gravity of a fluid with a weight density of 31.2 lb/ft is a. 2.00 b. 0.969 c. 0.500 d. 1.03

Engineering
1 answer:
kykrilka [37]3 years ago
7 0

Answer:

Answer is c 0.500

Explanation:

SpecificGravity=\frac{\rho _{fluid}*g}{\rho _{water}*g}

We know that \rho_{water}=62.42lb/ft^{3}

Applying values we get

SpecificGravity=\frac{31.2}{62.4}=0.5

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Technician A says that mechanical shifting controls can wear out over time. Technician B says that vacuum control rubber diaphra
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Based on the information, both technician A and technician B are correct.

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2 years ago
For metallurgical reasons, it is desirable to melt the weld metal with minimum energy input. Which one of the following heat sou
stellarik [79]

Answer:

The correct option is;

(a) High power density

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Tubing cutters for copper tube are only available in one stlye true or false
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3 0
3 years ago
Using the AASHTO procedure, determine the thickness required for a base and a surface layer over existing subgrade. The structur
garri49 [273]

Answer:

<u>the thickness required would be 12 inch HMA and granular base layer of 6 inches</u>

Explanation:

structural number = 4.5

stone base course material coefficient = 0.13

hma material layer coefficient = 0.40

drainage coefficient = 0.90

we will use layered analysis procedure to get thickness

D1 >= sN1/a1

when we cross multiply,

sN1 = a1D1 >=sN1

D2 >= -sN2-sN1/a2m2

sN2* + sN1* >= sN2

D3 >= sN3-(sN1*+sN2*)/a2m2

where a1,a2,a3 = layer coefficient

d1 d2 d3 = actual thickness

m2,m3 = coefficient of base

a1 = 0.4

a1 = 0.13

sN = 4.5

m2 = 0.9

D1 >= sN1/a1 = 4.5/0.4

= 11.25

thickness of surface = 12 inches

a1D1 = 0.4x12 = 4.8

we have value of sN2 = 5.5

(5.5 -4.8)/(0.13*0.9)

= 0.7/0.117

= 5.9829 inches

approximately 6 inches

so the pavement will have 12inch HMA surface and 6 inches granular base layer.

7 0
3 years ago
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