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jonny [76]
3 years ago
10

The specific gravity of a fluid with a weight density of 31.2 lb/ft is a. 2.00 b. 0.969 c. 0.500 d. 1.03

Engineering
1 answer:
kykrilka [37]3 years ago
7 0

Answer:

Answer is c 0.500

Explanation:

SpecificGravity=\frac{\rho _{fluid}*g}{\rho _{water}*g}

We know that \rho_{water}=62.42lb/ft^{3}

Applying values we get

SpecificGravity=\frac{31.2}{62.4}=0.5

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