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Alecsey [184]
3 years ago
8

Because there is a one-to-many relationship between sales reps and customers in the TAL Distributors database, one sales rep can

be associated with zero, one, or more customers.
True/False
Engineering
1 answer:
stiv31 [10]3 years ago
7 0

Answer:

True

Explanation:

The relationship between sales reps and customers is an example of a one-to-many relationship. This is because one sales rep can be associated with many customers but a customer must have one sales rep. It is impossible for a customer to have zero sales rep but this is quite possible for a sales rep to have either zero, one or even more customers. Therefore the statement is True.

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The total number of people whom have made machines is not a recorded figure? Need to be more specific :/

Explanation:

Sorry not very helpful, your question is REALLY broad

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3 years ago
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A flow of 100 mgd is to be developed from a 190-mi^2 watershed. At the flow line the area's reservoir is estimated to cover 3900
yaroslaw [1]

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13-mi 27 acres

Explanation:

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When you look at a drawing, how do you know if you are looking at US
Alborosie

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is it glizzy bread

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Two kilograms of air within a piston-cylinder assembly execute a Carnot power cycle with maximun1 and minimum temperatures of 75
ExtremeBDS [4]

Answer:

The Answer and Explanation is in the folloing attachment  

Explanation:

                                     

8 0
4 years ago
An asphalt concrete mixture includes 94% aggregates by weight. The specific gravity of aggregate and asphalt are 2.7 and 1.0, re
riadik2000 [5.3K]

Answer:

The correct solution is "5.74%".

Explanation:

The given values are:

Gravity of aggregate,

G_{agg}=2.7

Gravity of asphalt,

G_{asp}=1.0

Asphalt concrete mixture,

W_{agg}=0.94 \ W_m

We know that,

W_{asp}=W_m-W_{agg}

        =0.06 \ W_m

Now,

The theoretical specific gravity of mix,

⇒ G_t=\frac{W_{agg}+W_{asp}}{\frac{W_{agg}}{G_{agg}} +\frac{W_{asp}}{G_{asp}} }

By putting the values, we get

         =\frac{0.94 \ Wm+0.06 \ Wm}{\frac{0.94 \ Wm}{2.7} +\frac{0.06 \ Wm}{1} }

         =2.45

hence,

The percentage of voids will be:

⇒  %V = \frac{G_t-G_m}{G_t}\times 100

           = \frac{2.45-2.317}{2.45}\times 100

           = \frac{0.133}{2.317}\times 100

           = 5.74 (%)  

8 0
3 years ago
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