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Alecsey [184]
3 years ago
8

Because there is a one-to-many relationship between sales reps and customers in the TAL Distributors database, one sales rep can

be associated with zero, one, or more customers.
True/False
Engineering
1 answer:
stiv31 [10]3 years ago
7 0

Answer:

True

Explanation:

The relationship between sales reps and customers is an example of a one-to-many relationship. This is because one sales rep can be associated with many customers but a customer must have one sales rep. It is impossible for a customer to have zero sales rep but this is quite possible for a sales rep to have either zero, one or even more customers. Therefore the statement is True.

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Which of the following answers regarding Mealy and Moore Machines are true?
Rom4ik [11]

Answer:

suck bro ☺️☺️ lol

5 0
3 years ago
A step-up transformer has 20 primary turns and 400 secondary turns. If the primary current is 30 A, what is the secondary curren
-BARSIC- [3]
150
A
Explanation:
V
s
V
p
=
N
s
N
p

(
1
)
N
refers to the number of turns
V
is voltage
s
and
p
refer to the secondary and primary coil.
From the conservation of energy we get:
V
p
I
p
=
V
s
I
s

(
2
)
From
(
1
)
:
V
s
V
p
=
900
00
3
00
=
300
∴
V
s
=
300
V
p
Substituting for
V
s
into
(
2
)
⇒
V
p
I
p
=
300
V
p
×
0.5
∴
I
p
=
150
A
Seems a big current.
3 0
3 years ago
If you add 10 J of heat to a system so that the final temperature of the system is 200K, what is the change in entropy of the sy
Elden [556K]

Answer:

0.05 J/K

Explanation:

Given data in question

heat (Q) = 10 J

temperature (T) = 200 K

to find out

the change in entropy of the system

Solution

we will solve this by the entropy change equation

i.e  ΔS = ΔQ/T           ...................1

put the value of heat Q and Temperature T in equation 1

ΔS is the enthalpy change and T is the temperature

so  ΔS = 10/200

ΔS = 0.05 J/K

8 0
3 years ago
11. Ten bagels is what percentage of a dozen bagels?
IRINA_888 [86]

Answer:

the answer is d 83.3%

Explanation:

3 0
3 years ago
Exhaust gas from a furnace is used to preheat the combustion air supplied to the furnace burners. The gas, which has a flow rate
Monica [59]

Answer:

The total tube surface area in m² required to achieve an air outlet temperature of 850 K is 192.3 m²

Explanation:

Here we have the heat Q given as follows;

Q = 15 × 1075 × (1100 - t_{A2}) = 10 × 1075 × (850 - 300) = 5912500 J

∴ 1100 - t_{A2} = 1100/3

t_{A2}  = 733.33 K

\Delta \bar{t}_{a} =\frac{t_{A_{1}}+t_{A_{2}}}{2} - \frac{t_{B_{1}}+t_{B_{2}}}{2}

Where

\Delta \bar{t}_{a} = Arithmetic mean temperature difference

t_{A_{1} = Inlet temperature of the gas = 1100 K

t_{A_{2} = Outlet temperature of the gas = 733.33 K

t_{B_{1} =  Inlet temperature of the air = 300 K

t_{B_{2} = Outlet temperature of the air = 850 K

Hence, plugging in the values, we have;

\Delta \bar{t}_{a} =\frac{1100+733.33}{2} - \frac{300+850}{2} = 341\tfrac{2}{3} \, K = 341.67 \, K

Hence, from;

\dot{Q} = UA\Delta \bar{t}_{a}, we have

5912500  = 90 × A × 341.67

A = \frac{5912500  }{90 \times 341.67} = 192.3 \, m^2

Hence, the total tube surface area in m² required to achieve an air outlet temperature of 850 K = 192.3 m².

4 0
3 years ago
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