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Kaylis [27]
3 years ago
15

When passing another vehicle, when is it acceptable to drive over the

Engineering
2 answers:
miss Akunina [59]3 years ago
7 0

Answer:

Under no circumstances

Explanation:

I'm not 100% sure why, but I remember hearing that you're not suposed to go over the speed limit no matter what

Lisa [10]3 years ago
7 0

Answer:

correct option is B. Under no circumstances

Explanation:

solution

when we drive on the road and passing another vehicle

we will never cross the speed limit as provide by traffic department for good traffic movement

if we cross that limit it may be very danger and risky for our life and vehicle both

in USA approx all area have top speed limit is 55 mph

so in any circumstances we can not cross our speed limit

so correct option is B. Under no circumstances

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1. (15) A truck scale is made of a platform and four compression force sensors, one at each corner of the platform. The sensor i
Elanso [62]

Answer:

a). 139498.24 kg

b). 281.85 ohm

c). 10.2 ohm

Explanation:

Given :

Diameter, d = 22 m

Linear strain, $\epsilon$ = 3%

                        = 0.03

Young's modulus, E = 30 GPa

Gauge factor, k = 6.9

Gauge resistance, R = 340 Ω

a). Maximum truck weight

σ = Eε

σ = $0.03 \times 30 \times 10^9$

$\frac{P}{A} =0.03 \times 30 \times 10^9$

$P = 0.03 \times 30 \times 10^9\times \frac{\pi}{4}\times (0.022)^2$

 = 342119.44 N

For the four sensors,

Maximum weight = 4 x P

                            =  4 x 342119.44

                            = 1368477.76 N

Therefore, weight in kg is $m=\frac{W}{g}=\frac{1368477.76}{9.81}$

                     m = 139498.24 kg

b). Change in resistance

k=\frac{\Delta R/R}{\Delta L/L}

$\Delta R = k. \epsilon R$    , since $\epsilon= \Delta L/ L$

$\Delta R = 6.9 \times 0.03 \times 340$

$\Delta R = 70.38 $ Ω

For 4 resistance of the sensors,

$\Delta R = 70.38 \times 4 = 281.52$ Ω

c). $k=\frac{\Delta R/R}{\epsilon}$

If linear strain,

$\frac{\Delta R}{R} \approx \frac{\Delta L}{L}$  , where k = 1

$\Delta R = \frac{\Delta L}{L} \times R$

$\Delta R = 0.03 \times 340$

$\Delta R = 10.2 $ Ω

4 0
4 years ago
The Hubble space telescope is a bus-sized satellite powered by huge ___ panels
Artemon [7]

Answer:

Solar

Explanation:

The Hubble space telescope is a bus-sized satellite powered by huge solar panels.

4 0
3 years ago
Read 2 more answers
Explain why surface temperature increases when two bodies are rubbed against each other. What is the significance of temperature
Ronch [10]

Answer:

The surface temperature increases when two bodies are rubbed against each other due to friction.

Explanation:

No object has a perfectly even surface. So, when two bodies with uneven surfaces are rubbed against each other, they experience friction.

Friction is a resistance experienced by the two bodies when they are moved against each other.

The friction between the two surfaces, converts the kinetic energy of the movement to the thermal energy.

Thus, resulting in rise in the surface temperature of the two bodies.

Therefore, when two bodies are rubbed against each other, the surface temperature increases due to friction.

7 0
4 years ago
Which term refers to the impurities found during the welding process ?
Aleks04 [339]

Answer:

idk

Explanation:

idk

6 0
4 years ago
A particular motor rotates at 3000 revolutions per minute (rpm). What is its speed in rad/sec, and how many seconds does it take
raketka [301]

Answer:

ω=314.15 rad/s.

0.02 s.

Explanation:

Given that

Motor speed ,N= 3000 revolutions per minute

N= 3000 RPM

The speed of the motor in rad/s given as

Now by putting the values in the above equation

ω=314.15 rad/s

Therefore the speed in rad/s will be 314.15 rad/s.

The speed in rev/sec given as

ω= 50 rev/s

It take 1 sec to cover 50 revolutions

That is why to cover 1 revolution it take

\dfrac{1}{50}=0.02\ s

5 0
4 years ago
Read 2 more answers
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