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IgorC [24]
3 years ago
6

Raw materials used of silicone rubber

Engineering
2 answers:
n200080 [17]3 years ago
7 0

Answer:

Silicone rubber is an elastomer (rubber-like material) composed of silicone—itself a polymer—containing silicon together with carbon, hydrogen, and oxygen. Silicone rubbers are widely used in industry, and there are multiple formulations.

Explanation:

katen-ka-za [31]3 years ago
7 0
Silicone is identified as a synthetic elastomer as it is a polymer which displays viscoelasticity – that is to say it shows both viscosity and elasticity. Colloquially people call these elastic characteristics rubber. Silicone itself is made up of carbon, hydrogen, oxygen and silicon
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Answer:

28%

Explanation:

Although there are sources that says 30% of gross income can be spent on housing, the most reliable amount that can be spent (according to other sources) is 28%.

Take for instance, you earn $5000 monthly, the maximum that you can spend on housing is:

Max = 28\% * \$5000

Using a calculator, we have:

Max = \$1400

<em>The maximum that can be spent on a monthly gross income of $5000 is $1400</em>

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3 years ago
Which rigid motion maps the solid-line figure onto the dotted-line figure?
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A heat engine that rejects waste heat to a sink at 520 R has a thermal efficiency of 35 percent and a second- law efficiency of
xeze [42]

Answer:

The source temperature is 1248 R.

Explanation:

Second law efficiency of the engine is the ratio of actual efficiency to the maximum possible efficiency that is reversible efficiency.

Given:  

Temperature of the heat sink is 520 R.

Second law efficiency is 60%.

Actual thermal efficiency is 35%.

Calculation:  

Step1

Reversible efficiency is calculated as follows:

\eta_{II}=\frac{\eta_{a}}{\eta_{rev}}

0.6=\frac{0.35}{\eta_{rev}}

\eta_{rev}=0.5834

Step2

Source temperature is calculated as follows:

\eta_{rev}=1-\frac{T_{L}}{T}

\eta_{rev}=1-\frac{520}{T}

0.5834=1-\frac{520}{T}

T = 1248 R.

The heat engine is shown below:

Thus, the source temperature is 1248 R.

6 0
3 years ago
Determine an expression in standard form for the voltage gain VoVs. Hv(jω)=Vo(jω)Vi(jω)=R2R111+jωCR2 Hv(jω)=Vo(jω)Vi(jω)=−R2R111
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VashaNatasha [74]

Answer:

Disaggregation

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