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3 years ago

14

A total of 396 tickets were sold for the school play. They wee either adult tickets or student tickets. The number of student ti

ckets sold was three times of adult tickets sold. How many adult tickets were sold?

1 answer:

Flura [38]3 years ago

7 0

We know that this problem is in the ratio of 1:3 1 being adult tickets and 3 being student tickets. If we divide 396 by 4 to get 1 part, then we have the answer.

396/4=99

Answer: 99 adult tickets

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Pls solve the simultaneous equation in the attachment.

siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

$\frac{x}{2}-\frac{y}{5}=1$ ----> equation A

$y-\frac{x}{3}=8$ ----> equation B

Multiply equation A by 10 both sides to remove the fractions

$5x-2y=10$ ----> equation C

isolate the variable y in equation B

$y=\frac{x}{3}+8$ ----> equation D

we have the system of equations

$5x-2y=10$ ----> equation C

$y=\frac{x}{3}+8$ ----> equation D

Solve the system by substitution

substitute equation D in equation C

$5x-2(\frac{x}{3}+8)=10$

solve for x

$5x-\frac{2x}{3}-16=10$

Multiply by 3 both sides

$15x-2x-48=30$

$15x-2x=48+30$

Combine like terms

$13x=78$

$x=6$

<em>Find the value of y</em>

$y=\frac{x}{3}+8$

$y=\frac{6}{3}+8$

$y=10$

The solution is the ordered pair (6,10)

Part b) we have

$xy=21$ ---> equation A

$x+5y=22$ ----> equation B

isolate the variable x in the equation B

$x=22-5y$ ----> equation C

substitute equation C in equation A

$(22-5y)y=21$

solve for y

$22y-5y^2=21$

$5y^2-22y+21=0$

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

$x=22-5(1.4)=15$

For y=3

$x=22-5(3)=7$

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The solutions are the ordered pairs (7,3) and (15,1.4)

3 0

3 years ago

What is the square root of four

xz_007 [3.2K]

Answer:

It is +2 or since (+2)*(+2 ) gives. If you think that it would be (-2) also then you are wrong because root of a positive rational number is always positive number.

Step-by-step explanation:

Let the square root of four be ‘k’.

Then we have

(4)^1/2=k

(Squaring both sides)

4=(k)^2

=>(k)^2–4=0

=>(k)^2-(2)^2=0

=>[k+2][k-2]=0 {since (a)^2-(b)^2=(a+b)(a-b)}

if product of two numbers is 0 then either of one must be zero.

If k+2=0 then k=-2

If k-2=0 then k=2

From here we got two answers but -2 should be omitted because when we square an equation we add “root extra”which means that when we square an equation one root is added.

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3 years ago

How can Ari simplify the following expression? StartFraction 5 Over a minus 3 EndFraction minus 4 divided by 2 + StartFraction 1

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Answer:

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Step-by-step explanation:

Given

$\frac{5}{-3} - \frac{4}{2} + \frac{1}{-3}$

Required

Simpify

The very first step is to take LCM of the given expression

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Perform arithmetic operations o the numerator

$-\frac{16}{6}$

Divide the numerator and denominator by 2

$-\frac{16/2}{6/2}$

$-\frac{8}{3}$

The expression can't be further simplified;

Hence, $\frac{5}{-3} - \frac{4}{2} + \frac{1}{-3}$ = $-\frac{8}{3}$

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3 years ago

If (42)^p = 41^4, what is the value of p?

babymother [125]

First you need to make both bases the same:

Lets remove the ^p and ^4

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X - ln(42) / ln(41) = 1.00648904

Now you have 41^1.00648904(p) = 41^4

Now the bases are equal so we need to set the exponents to equal:

1.00648904(p) = 4

Divide both sides by 1.00648904 to solve for P

P = 4 / 1.00648904

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3 years ago

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