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Alexeev081 [22]
3 years ago
11

Convert 2.8 radians to degree measure. Round your answer to the nearest hundredth.​

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
8 0

Answer:

16.04°

Step-by-step explanation:

2.8 \: rad = x \: degrees \\

1rad × 180/π = 57.296°

x = 2.8 \times  \frac{180}{\pi}  = 16.0428 \\ x = 16.04

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While reviewing his budget, Andre calculated his variable and total expenses for last month: variable expenses: $2,863.09 total
Elenna [48]

Answer:

Fixed expenses = 1767.07

Step-by-step explanation:

Andre calculated his variable and total expenses for last month.

His variable expenses is $2,863.09

His total expenses is $4,630.16

Now, Total expenses = Variable expenses + Fixed expenses

So, Fixed expenses = Total expenses - Variable expenses

⇒ F = T - V

⇒ F = 4630.16 - 2863.09

⇒ F = 1767.07

So, this the equation to represent Andre's fixed income. (Answer)            

7 0
3 years ago
Read 2 more answers
For each part, give a relation that satisfies the condition. a. Reflexive and symmetric but not transitive b. Reflexive and tran
Vesnalui [34]

Answer:

For the set X = {a, b, c}, the following three relations satisfy the required conditions in (a), (b) and (c) respectively.

(a) R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)} is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)} is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)} is symmetric and transitive but not reflexive .

Step-by-step explanation:

Before, we go on to check these relations for the desired properties, let us define what it means for a relation to be reflexive, symmetric or transitive.

Given a relation R on a set X,

R is said to be reflexive if for every a \in X, (a,a) \in R.

R is said to be symmetric if for every (a, b) \in R, (b, a) \in R.

R is said to be transitive if (a, b) \in R and (b, c) \in R, then (a, c) \in R.

(a) Let R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)}.

Reflexive: (a, a), (b, b), (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \implies (b, a) \in R

Therefore R is symmetric.

Transitive: (a, b) \in R \ and \ (b, c) \in R but but (a,c) is not in  R.

Therefore, R is not transitive.

Therefore, R is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)}

Reflexive: (a, a), (b, b) \ and \ (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \ but \ (b, a) \not \in R

Therefore R is not symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)}

Reflexive: (a, a) \in R but (b, b) and (c, c) are not in R

R must contain all ordered pairs of the form (x, x) for all x in R to be considered reflexive.

Therefore, R is not reflexive.

Symmetric: (a, b) \in R and (b, a) \in R

Therefore R is symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is symmetric and transitive but not reflexive .

4 0
3 years ago
Given the function g(x)=−2x−8, evaluate g(0).
Vera_Pavlovna [14]

Answer:

g(0) = -8

Step-by-step explanation:

When you plug in a zero for the x the equation will look like

g(0) = -2(0) - 8

-2 times 0 = 0 so g(0) = -8

7 0
3 years ago
Brianna has a 50$ online gift certificate from a book store. The cost of each book is $9. There is also a shipping charge of 5$
ZanzabumX [31]

Answer:

5 books

Step-by-step explanation:

I just went through the nines multiplication table until I got to 9 * 5 which equals 45, and then since it charges $5 for the shipping fee, $45 + $5 = $50 so 5 books would be the amount she can buy

6 0
3 years ago
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Simplify the following radicals (in exponential notation) (x^9y^6z^15)^1/3
MAVERICK [17]

\bf (x^9y^6z^{15})^{\frac{1}{3}}\implies \stackrel{\textit{distributing the exponent}}{\left(x^{9\cdot \frac{1}{3}}y^{6\cdot \frac{1}{3}} z^{15\cdot \frac{1}{3}} \right)}\implies x^3y^2z^5

8 0
4 years ago
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