Answer:
B
Step-by-step explanation:
Total segment bought=190+27=217 segments
Total length of the whole anchor=217*9/2=1953/2=976 1/2 meters
The area of the shaded region is 40π/3 square cm if the radius of the small circle r is 3 cm and the radius of the large circle R is 7 cm.
<h3>What is a circle?</h3>
It is described as a set of points, where each point is at the same distance from a fixed point (called the center of a circle)
We have a circle in which the shaded region is shown.
The radius of the small circle r = 3 cm
The radius of the large circle R = 3+4 = 7 cm
The area of the shaded region:
= area of the large circle sector - an area of the small circle sector
= (120/360)[π7²] - (120/360)[π3²]
= 49π/3 - 3π
= 40π/3 square cm or
= 13.34π square cm
Thus, the area of the shaded region is 40π/3 square cm if the radius of the small circle r is 3 cm and the radius of the large circle R is 7 cm.
Learn more about circle here:
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X=275+55= 330 biked
y=275-55= 220 bus
The correct answer is: [D]: " 4x² − 12x − 4 " .
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Explanation:
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Given:
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" (16x² − 16) + ( -12x² − 12x + 12) " ; Simplify.
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Note the "distributive property of multiplication:
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a(b + c) = ab + ac ;
a(b − c) = ab − ac .
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So we can rewrite the expression as:
" (16x² − 16) + 1( -12x² − 12x + 12) " ;
{The "1" is implied; since "1", multiplied by any value, results in the exact same value.}.
Let us examine the following part of the expression:
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" + 1 ( -12x² − 12x + 12 ) " ;
Using the distributive property of multiplication:
" + 1 ( -12x² − 12x + 12 ) = (1 * -12x²) − (1 * 12x) + (1 * 12) ;
= " − 12x² − 12x + 12 " ;
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Now, bring down the other part of the expression; & rewrite:
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→ " (16x² − 16) − 12x² − 12x + 12 " ;
→ " 16x² − 16 − 12x² − 12x + 12 " ;
Now, combine the "like terms" :
+ 16x² − 12x² = 4x² ;
− 16 + 12 = -4 ;
and we have " − 12x" ;
So we can rewrite the expression as:
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→ " 4x² − 12x − 4 " ;
→ which is: "Answer choice: [D]: " 4x² − 12x − 4 <span>" .
</span>_______________________________________________________
Answer:
m+n=9
Step-by-step explanation:
Put the equation into the form ka^mb^n by multiplying the coefficients (-1*2*-3), so k= 6, then add the exponents of a together, a^2+a^1= a^3, m=3.
Now you have 6a^3, next we do the exponents of b together, b^3, b^2, b^1= b^6, n=6.
This is 6a^3b^6. m=3 and b=6, so add m+n=9.