The solution set of the equation x^2 + 2x - 48 = 0 is x = -1 ± 7
<h3>How to determine the solution set of the equation?</h3>
The equation is given as:
x^2 + 2x - 48 = 0
A quadratic equation is represented as:
ax^2 + bx + c = 0
By comparing both equations, we have
a = 1, b = 2 and c = -48
The solution of the quadratic equation is then calculated using
x = (-b ± √(b^2 - 4ac))/2a
Substitute values for a, b and c in the above equation
x = (-2 ± √(2^2 - 4 * 1 * -48))/2 * 1
This gives
x = (-2 ± √196)/2
Evaluate the square root of 196
x = (-2 ± 14)/2
Divide through by 2
x = -1 ± 7
Hence, the solution set of the equation x^2 + 2x - 48 = 0 is x = -1 ± 7
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Answer:
This is a triangle with 2 equal angles and equal to 60
=> this is an equilateral triangle
=> y = 60
4x.3 = 54
=> y = 60
x = 54/12 = 4.5
Step-by-step explanation:
Answer:
A + B = 2
Step-by-step explanation:
If A=1 and B=1 then it is 1 plus 1 which is 2
Answer:
The first graph
Step-by-step explanation:
The second graph does not have a point at (1, -2).
The answer is c. contribute
