Question

14. The Achilles tendon inserts on the calcaneus (the heel bone) at a distance of 8 cm from the axis of the ankle joint. If the force generated by the muscles attached to the Achilles tendon is 3000 N, and the moment arm of this force about the ankle joint is 5 cm, what torque is created by these muscles about the ankle joint? Hopefully it’s enough torque to move out of the way so the arrow doesn’t shoot through the tendon.

Answer 1

Answer:

150 Nm

Explanation:

Unit conversion:

5 cm = 0.05 m

8 cm = 0.08 m

The torque generated by such force would be the product of the force by the muscles and the moment arm of that force.

T = FR

Where T is the torque (Nm), F = 3000 N is the force and R = 0.05 m is the moment arm

T = 3000*0.05 = 150 Nm

Answer 2

Answer:

The torque is  $T=150Nm$

Explanation:

The diagram showing this muscle is shown on the first uploaded image

     From the question we are told that

     Distance of insertion is  $D_i = 8cm = 0.08m$

     Force generated is  $F_A = 3000N$

    The moment arm of the force about the ankle joint is  $D_A = 5cm = 0.05m$

Generally the Torque is mathematically represented as

                      $T = F * D_A$

                         $= 3000 *0.05$

                         $=150Nm$