Answer:
Explanation:
Let m be the mass of cylinder and r be the radius. It is moving with velocity v and angular velocity is ω. Let I be the moment of inertia of the cylinder.
I = 0.5 mr²
Total kinetic energy, T = 0.5 mv² + 0.5 Iω²
T = 0.5 (mv² + 0.5 mr²ω²)
v = rω
So, T = 0.5 (mv² + 0.5 mv²) = 0.75 mv²
Rotational kinetic energy is
R = 0.5 Iω² = 0.5 x 0.5 mr²ω²
R = 0.25 mv²
So, R / T = 0.25 / 0.75 = 1/3
Answer:
81 J.
Explanation:
From the question given above, the following data were obtained:
Specific heat capacity (C) = 0.45 J/gK.
Temperature change (ΔT) = 15 K
Mass = 12 g
Heat required (Q) =?
The heat required to raise the temperature of iron can be obtained as illustrated below:
Q = MCΔT
Q = 12 × 0.45 × 15
Q = 81 J
Therefore, the heat required to raise the temperature of the iron is 81 J.
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