Answer: = 5.75 × 10 -6
Explanation:
= 5.75 × 10-6
(scientific notation)
= 5.75e-6
(scientific e notation)
= 5.75 × 10-6
(engineering notation)
(millionth; prefix micro- (u))
= 0.00000575
(real number)
The correct answer would be left
Answer:
The answer is "
"
Explanation:
For point a:
Energy balance equation:


From the above equation:

because the rate of air entering the tank that is
constant.
Since the tank was initially empty and the inlet is constant hence,
Interpolate the enthalpy between
. The surrounding air
temperature:

Substituting the value from ideal gas:

Follow the ideal gas table.
The
and between temperature
Interpolate

Substitute values from the table.
For point b:
Consider the ideal gas equation. therefore, p is pressure, V is the volume, m is mass of gas.
(M is the molar mass of the gas that is
and R is gas constant), and T is the temperature.


For point c:
Entropy is given by the following formula:

Answer:

Explanation:
The inlet specific volume of air is given by:

The mass flow rates is expressed as:

The energy balance for the system can the be expresses in the rate form as:
![E_{in}-E_{out}=\bigtriangleup \dot E=0\\\\E_{in}=E_{out}\\\\\dot m(h_1+0.5V_1^2)=\dot W_{out}+\dot m(h_2+0.5V_2^2)+Q_{out}\\\\\dot W_{out}=\dot m(h_2-h_1+0.5(V_2^2-V_1^2))=-m({cp(T_2-t_1)+0.5(V_2^2-V_1^2)})\\\\\\\dot W_{out}=-(10.42lbm/s)[(0.25\frac{Btu}{lbm.\textdegree F})(300-900)\textdegree F+0.5((700ft/s)^2-(350ft/s)^2)(\frac{1\frac{Btu}{lbm}}{25037ft^2/s^2})]\\\\\\\\=1486.5\frac{Btu}{s}](https://tex.z-dn.net/?f=E_%7Bin%7D-E_%7Bout%7D%3D%5Cbigtriangleup%20%5Cdot%20E%3D0%5C%5C%5C%5CE_%7Bin%7D%3DE_%7Bout%7D%5C%5C%5C%5C%5Cdot%20m%28h_1%2B0.5V_1%5E2%29%3D%5Cdot%20W_%7Bout%7D%2B%5Cdot%20m%28h_2%2B0.5V_2%5E2%29%2BQ_%7Bout%7D%5C%5C%5C%5C%5Cdot%20W_%7Bout%7D%3D%5Cdot%20m%28h_2-h_1%2B0.5%28V_2%5E2-V_1%5E2%29%29%3D-m%28%7Bcp%28T_2-t_1%29%2B0.5%28V_2%5E2-V_1%5E2%29%7D%29%5C%5C%5C%5C%5C%5C%5Cdot%20W_%7Bout%7D%3D-%2810.42lbm%2Fs%29%5B%280.25%5Cfrac%7BBtu%7D%7Blbm.%5Ctextdegree%20F%7D%29%28300-900%29%5Ctextdegree%20F%2B0.5%28%28700ft%2Fs%29%5E2-%28350ft%2Fs%29%5E2%29%28%5Cfrac%7B1%5Cfrac%7BBtu%7D%7Blbm%7D%7D%7B25037ft%5E2%2Fs%5E2%7D%29%5D%5C%5C%5C%5C%5C%5C%5C%5C%3D1486.5%5Cfrac%7BBtu%7D%7Bs%7D)
Hence, the mass flow rate of the air is 1486.5Btu/s
Answer:
friction, conduction and induction
Explanation:
Had it in class I had it correct hope this helps.