I need some help please !! :)

Fine the surface of one yard.<br><br>please help .-.

ale4655 [162]

Answer:

1) 34 square meters

2) 21 square yards

Step-by-step explanation:

1) 7x4=28

1/2x3x2x2=6

28+6= 34 square meters

2)3x3=9

1/2x3x2x4=12

9+12= 21 square yards

6 0

2 years ago

3. A kite is aloft at the end of a 1500 foot string. The string make an angle of 43° with the

sineoko [7]

Answer:

$h= 1500\,*\,sin(43^o)$

Step-by-step explanation:

Notice that there is a right angle triangle formed with sides as follows:

hypotenuse is the actual 1500 ft string. The acute angle 43 degrees is opposite to the segment that represents the height of the kite from the ground. Therefore, the trigonometric ratio that we can use to find that opposite side to the given angle, is the sine function as shown below:

$sin(43^o) = \frac{opposite}{hypotenuse} \\sin(43^o) = \frac{opposite}{1500}\\opposite = 1500\,*\,sin(43^o)\\h= 1500\,*\,sin(43^o)$

8 0

3 years ago

Two buildings are 200 feet apart. The height of the taller building is 50 ft. The angle of depression from the top of the taller

Goshia [24]

Regergregegergergergergegerge

3 0

3 years ago

Read 2 more answers

A newspaper’s cover page is 3/8 text, and photographs fill the rest. If 2/5 of the text is an article about endangered species,

jolli1 [7]

Answer:

$\frac{3}{20}$

Step-by-step explanation:

Let x be the cover page

We are given that a newspaper 's cover page is $\frac{3}{8}$ text and photograph fill the rest.

We have to find that how much part of cover's page is the article about endangered species

Text = $\frac{3}{8}x$

Remaining part = $x-\frac{3}{8} x$

Remaining part = $\frac{8x-3x}{8}=\frac{5}{8} x$

Therefore, a newspaper;s cover page fill with Photograph = $\frac{5}{8}$

If the article about endangered species= $\frac{2}{5}$ of text

Therefore, the article about endangered species= $\frac{2}{5}\times\frac{3x}{8}=\frac{3}{20}x$

Hence, the article about endangered species is $\frac{3}{20}$ of the cover page.

7 0

3 years ago

Read 2 more answers

The tortoise and the hare are in a road race to defend the honor of their breed. the tortoise crawls the entire 1000. m distance

jolli1 [7]

<span>The tortoise crawls the whole 1000 m at 0.2 m/s, therefore, you must divide the distance by the rate of travel to find the time it took to complete the race. This gives us a time of 5,000 seconds to crawl the thousand meters. The hare runs the first 200 meters at 2 m/s, meaning that takes 100 seconds. The last 800 meters divided by the speed of 3 m/s gives us a time of 266 seconds. These two numbers must be added to the hare's rest time, converted from 1.3 hours into seconds by multiplying that number by 60 (for minutes in an hour) then 60 again (for seconds in a minute). 1.3 hours is equal to 4680 seconds. Therefore, the whole race took the hare 5,046 seconds, making it slightly slower than the hare, who finished in 5,000 seconds flat.</span>

5 0

3 years ago