Ask question

Ask question

All categories

3 years ago

12

. Solve each given equation and show your work. Tell whether each equation has one solution, an infinite number of solutions, or

no solution. Explain your answers. (a) 4 +2( − 1) = 10 + 2 (b) 30 − = 10 − (6 +10) (c) 8x = 4x + 4x +10(x − x)
PLEASE HELP ASAP

1 answer:

DerKrebs [107]3 years ago

6 0

No Solution

No Solution

All real numbers

Any number in place of x makes the equation true

You might be interested in

Nine less than a number is no more than 8 and is no less than 3

frozen [14]

9 - x < 8 => -x < 8 - 9 => -x < -1 => x > 1

9 - x > 3 => -x > 3 -9 => -x > -6 => x < 6

So the number is between 1 and 6, notation 1 < x < 6

7 0

4 years ago

Please help me asap!!

Xelga [282]

Answer:

50

Step-by-step explanation:

Fjfifjrjri I have to have a set amount of characters, but I am too lazy to research and write the explanation. I'm sorry.

7 0

3 years ago

to approach the runway, a pilot of a small plane must begin a 10 degree descent from a height of 1790 feet above the ground. To

vodomira [7]

2.0 miles is the answer

3 0

4 years ago

Read 2 more answers

How to convert 1 5/6

AfilCa [17]

Answer:

11/6 as an improper fraction

Step-by-step explanation:

1 5/6 is 11/6 as an importer fraction and 1.86 as a decimal

8 0

4 years ago

2x^2+2y^2+6x-8y+12=0

lord [1]

Answer:

see explanation

Step-by-step explanation:

The equation of a circle in general form is

x² + y² + 2gx + 2fy + c = 0

with centre = (- g, - f) and radius = $\sqrt{g^2+f^2-c}$

Given

2x² + 2y² + 6x - 8y + 12 = 0 ← divide through by 2

x² + y² + 3x - 4y + 6 = 0 ← in general form

Compare like terms

2g = 3 ⇒ g = $\frac{3}{2}$

2f = - 4 ⇒ f = - 2 and c = 6, thus

centre = ( - $\frac{3}{2}$ , 2 ) and

radius = $\sqrt{(3/2)^2+(-2)^2-6}$

= $\sqrt{\frac{9}{4}+4-6 }$ = $\sqrt{\frac{1}{4} }$ = $\frac{1}{2}$

6 0

3 years ago