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DIA [1.3K]
3 years ago
9

Write the equation of a line over which A(-3,5) reflects to A’(2,-5). BRAINLIEST TO THE 1ST PERSON!!

Mathematics
2 answers:
skad [1K]3 years ago
8 0
<u>Given two points:</u>
A = (x₁,y₁) = (-3,5)
A' = (x₂,y₂) = (2,-5)

<u>Find the midpoint of point A and point A'</u>
The midpoint of the two points lies on the reflection line. You can find the midpoint by this following formula
x midpoint = \dfrac{x_{1}+x_{2}}{2}
y midpoint = \dfrac{y_{1}+y_{2}}{2}

Plug in the numbers
x midpoint = \dfrac{-3+2}{2}
x midpoint = \dfrac{-1}{2}
x midpoint = -0.5

y midpoint = \dfrac{5+(-5)}{2}
y midpoint = \dfrac{0}{2}
y midpoint = 0

The midpoint is
(x,y) = (-0.5, 0)

<u>Find the slope of the line passes through (-3,5) and (2,-5)</u>
Use this following formula to find the slope
m = \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

Plug in the numbers
m = \dfrac{-5-5}{2-(-3)}
m = \dfrac{-10}{2+3}
m = -10/5
m = -2

<u>Find the slope of the line which is perpendicular to the line that passes through (-3,5) and (2,-5)</u>
The line whose slope we want to find is the reflection line we are looking for. Two perpendicular lines have the rule of slope as follows.
m₁ × m₂ = -1

Input the numbers
-2 × m₂ = -1
m₂ = \dfrac{-1}{-2}
m₂ = \dfrac{1}{2}

<u>Find the line equation</u>
The reflection line has the slope of 1/2 and passes through the midpoint (-0.5, 0)
The formula to find a line equation:
y - y₁ = m(x - x₁)

Input the numbers (m = 1/2, x₁ = -0.5, y = 0)
y - y₁ = m(x - x₁)
y - 0 = 1/2 (x - (-0.5))
y = 1/2 (x + 0.5)
y = \frac{1}{2}x+0.25
This is the line equation
laila [671]3 years ago
6 0
Not sure but (-2,5) and (1,3)
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8 0
2 years ago
What is the equation of the line that goes through (2, -1) and is parallel to y=<br> 3x - 3?
larisa86 [58]

Answer:

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Step-by-step explanation:

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Afina-wow [57]

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