(2^8 ⋅ 3^−5 ⋅ 6^0)^−2 ⋅ 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 ⋅ 2^28 (5 points)
1 answer:
Answer:
Step-by-step explanation:
(2^8 ⋅ 3^−5 ⋅ 6^0)^−2 ⋅ 3
(2^8 ⋅ 3^−5 ⋅ 6^0)^−6
(a^m)^n=a^m*n
So,
(2^8*-6) * (3^−5*-6) * (6^0*-6)
(2^-48) (3^30) (6^0)
a^0=1
So,
(2^-48) (3^30) (1)
<u>(2^-48) (3^30)</u>
I hope this helps you friend!
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