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Jobisdone [24]
3 years ago
6

__: 11 = 1/3 : 6 is a math problem about ratios. Please solve!!

Mathematics
1 answer:
katen-ka-za [31]3 years ago
6 0

Answer:

A proportion is an equation that says that the two ratios are equivalent.

A proportion is read as a is to b as c is to d ,

\frac{a}{b}= \frac{c}{d} where b,d≠0

Given: \_:11=\frac{1}{3} :6

x:11=\frac{1}{3} :6

to find the value of x:

we can write above expression as :  \frac{x}{11} =\frac{\frac{1}{3}}{6}

Cross- Multiplication method: which means that we multiply the numerator of each side by the denominator of the other side.

Using cross multiplication method, we can solve the value of x:

6\cdot x=\frac{11}{3}

On simplifying:

x=\frac{11}{3\cdot 6}=\frac{11}{18}

Therefore, the value of x is, \frac{11}{18}






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7. The length of time (in months after maintenance) until failure of a bank’s surveillance television equipment follows a Weibul
cupoosta [38]

Answer:

The frequency by which the equipment should receive periodic maintenance is   x= 13.59

Step-by-step explanation:

A Wellbull distribution is mathematically represented as

            f(x,\alpha, \beta  ) = \left \{ { {\frac{\alpha }{\beta^{\alpha } }x^{\alpha -1} e^{-[\frac{x}{\beta } ]^\alpha} \ \ \ \  \ \ \\ \\ , x \ge0} \atop {0 \ \ \ \ \ \ \ \  Otherwise }} \right.

Where x is the frequency that the equipment should receive periodic maintenance  

probability of a breakdown before the next scheduled maintenance is mathematically represented as

                 P(x) = \int\limits^x_0 {\frac{\alpha }{\beta^{\alpha } } x^{\alpha -1 } e^{-[\frac{x}{\beta } ]^{\alpha }} } \, dx

Substituting 2 for \alpha and 60 for \beta 0.05 for P(x)

               0.05 = \int\limits^x_0 {\frac{2}{60^2} x^{2-1} e^{-[\frac{x}{60}]^2  } \, dx

              0.05 = \frac{2}{3600}\int\limits^x_0 {xe^{[-\frac{x^2}{3600} ]}} \, dx

Let v = - \frac{x^2}{3600}

=>  dv = \frac{-xdx}{1800}

=>  -xdx = 1800\ dv

Multiply both sides by minus

=> xdx = -1800dv

Substituting this into the equation

          0.05 = \frac{2}{3600} \int\limits^x_0 {-1800 e^u} \, du

Integrating and substituting back for x

           0.05 = -\frac{1800}{1800} [e^{[-\frac{x^2}{3600} ]}]\left {{x} \atop {0}} \right.

    substituting for  the range of x and 0

          0.05 = -  [e^{-[\frac{x^2}{3600}]  } -1]

          0.05 = -e^{[-\frac{x^2}{3600} ]} +1

          0.05 -1 = -e^{-\frac{x^2}{3600} }

         -0.95 = -e^{[-\frac{x^2}{3600} ]}

         0.95 = e^{[-\frac{x^2}{3600} ]}

Taking ln of both sides

      -0.05129 = - \frac{x^2}{3600}

     making x the  subject of the formula

        x = \sqrt{0.05129 * 3600 }

           x= 13.59

       

         

         

               

4 0
3 years ago
Help me pls it is on a time i got 30 minutes left
shepuryov [24]

Answer:

C.

Step-by-step explanation:

sorry if im wrong

5 0
3 years ago
Read 2 more answers
A landscaping company placed two orders with a nursery. First order was 5 bushes and 8 trees,and totaled $374.The second order w
Ede4ka [16]

Answer:For one bush it would be $185 and for one tree it would be $189.

Step-by-step explanation:185 + 189 = 374

8 0
3 years ago
What is the equation of a line that is perpendicular to -x+3y=9 and passes through point (-3,2)
Lynna [10]

Answer:

The perpendicular line would be y = -3x - 7

Step-by-step explanation:

To find the equation of the line, we first need to solve the original line for y.

-x + 3y = 9

3y = x + 9

y = 1/3x + 3

Now we know the slope of the original line to be 1/3. Since perpendicular lines have opposite and reciprocal slope, we know the new line to have a slope of -3. We can then use that along with the given point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 2 = -3(x + 3)

y - 2 = -3x - 9

y = -3x - 7

8 0
4 years ago
Mr mehra spends 30% of his income in food 10% on charity 25% and is left with 15750 what is his salary? find his savings
nalin [4]

Answer:

Mr mehra's salary is 26250

Step-by-step explanation:

suppose,

Mr mehra's salary is x

so,

He spends in food = 30% of x

                               =(30/100) . x      [x%=x/100]

                                = 30x/100

                                =3x/10

He spends in charity =10% of x

                                    =10x/100

                                    =x/10

Money left = 15750

so,

x = 3x/10 + x/10 +  15750

⇒x - 3x/10 - x/10 = 15750

⇒(10x-3x-x) /10 = 15750

⇒6x/10 = 15750

⇒6x=157500

⇒x = 157500/6

⇒x = 26250

∴Mr mehra's salary is 26250

5 0
3 years ago
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