Answer:
The frequency by which the equipment should receive periodic maintenance is
Step-by-step explanation:
A Wellbull distribution is mathematically represented as
![f(x,\alpha, \beta ) = \left \{ { {\frac{\alpha }{\beta^{\alpha } }x^{\alpha -1} e^{-[\frac{x}{\beta } ]^\alpha} \ \ \ \ \ \ \\ \\ , x \ge0} \atop {0 \ \ \ \ \ \ \ \ Otherwise }} \right.](https://tex.z-dn.net/?f=f%28x%2C%5Calpha%2C%20%5Cbeta%20%20%29%20%3D%20%5Cleft%20%5C%7B%20%7B%20%7B%5Cfrac%7B%5Calpha%20%7D%7B%5Cbeta%5E%7B%5Calpha%20%7D%20%7Dx%5E%7B%5Calpha%20-1%7D%20e%5E%7B-%5B%5Cfrac%7Bx%7D%7B%5Cbeta%20%7D%20%5D%5E%5Calpha%7D%20%5C%20%5C%20%5C%20%5C%20%20%5C%20%5C%20%5C%5C%20%5C%5C%20%2C%20x%20%5Cge0%7D%20%5Catop%20%7B0%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%20Otherwise%20%7D%7D%20%5Cright.)
Where x is the frequency that the equipment should receive periodic maintenance
probability of a breakdown before the next scheduled maintenance is mathematically represented as
![P(x) = \int\limits^x_0 {\frac{\alpha }{\beta^{\alpha } } x^{\alpha -1 } e^{-[\frac{x}{\beta } ]^{\alpha }} } \, dx](https://tex.z-dn.net/?f=P%28x%29%20%3D%20%5Cint%5Climits%5Ex_0%20%7B%5Cfrac%7B%5Calpha%20%7D%7B%5Cbeta%5E%7B%5Calpha%20%7D%20%7D%20x%5E%7B%5Calpha%20-1%20%7D%20e%5E%7B-%5B%5Cfrac%7Bx%7D%7B%5Cbeta%20%7D%20%5D%5E%7B%5Calpha%20%7D%7D%20%7D%20%5C%2C%20dx)
Substituting 2 for
and 60 for
0.05 for P(x)
![0.05 = \int\limits^x_0 {\frac{2}{60^2} x^{2-1} e^{-[\frac{x}{60}]^2 } \, dx](https://tex.z-dn.net/?f=0.05%20%3D%20%5Cint%5Climits%5Ex_0%20%7B%5Cfrac%7B2%7D%7B60%5E2%7D%20x%5E%7B2-1%7D%20e%5E%7B-%5B%5Cfrac%7Bx%7D%7B60%7D%5D%5E2%20%20%7D%20%5C%2C%20dx)
![0.05 = \frac{2}{3600}\int\limits^x_0 {xe^{[-\frac{x^2}{3600} ]}} \, dx](https://tex.z-dn.net/?f=0.05%20%3D%20%5Cfrac%7B2%7D%7B3600%7D%5Cint%5Climits%5Ex_0%20%7Bxe%5E%7B%5B-%5Cfrac%7Bx%5E2%7D%7B3600%7D%20%5D%7D%7D%20%5C%2C%20dx)
Let 
=> 
=> 
Multiply both sides by minus
=> 
Substituting this into the equation

Integrating and substituting back for x
![0.05 = -\frac{1800}{1800} [e^{[-\frac{x^2}{3600} ]}]\left {{x} \atop {0}} \right.](https://tex.z-dn.net/?f=0.05%20%3D%20-%5Cfrac%7B1800%7D%7B1800%7D%20%5Be%5E%7B%5B-%5Cfrac%7Bx%5E2%7D%7B3600%7D%20%5D%7D%5D%5Cleft%20%7B%7Bx%7D%20%5Catop%20%7B0%7D%7D%20%5Cright.)
substituting for the range of x and 0
![0.05 = - [e^{-[\frac{x^2}{3600}] } -1]](https://tex.z-dn.net/?f=0.05%20%3D%20-%20%20%5Be%5E%7B-%5B%5Cfrac%7Bx%5E2%7D%7B3600%7D%5D%20%20%7D%20-1%5D)
![0.05 = -e^{[-\frac{x^2}{3600} ]} +1](https://tex.z-dn.net/?f=0.05%20%3D%20-e%5E%7B%5B-%5Cfrac%7Bx%5E2%7D%7B3600%7D%20%5D%7D%20%2B1)

![-0.95 = -e^{[-\frac{x^2}{3600} ]}](https://tex.z-dn.net/?f=-0.95%20%3D%20-e%5E%7B%5B-%5Cfrac%7Bx%5E2%7D%7B3600%7D%20%5D%7D)
![0.95 = e^{[-\frac{x^2}{3600} ]}](https://tex.z-dn.net/?f=0.95%20%3D%20e%5E%7B%5B-%5Cfrac%7Bx%5E2%7D%7B3600%7D%20%5D%7D)
Taking ln of both sides

making x the subject of the formula


Answer:
C.
Step-by-step explanation:
sorry if im wrong
Answer:For one bush it would be $185 and for one tree it would be $189.
Step-by-step explanation:185 + 189 = 374
Answer:
The perpendicular line would be y = -3x - 7
Step-by-step explanation:
To find the equation of the line, we first need to solve the original line for y.
-x + 3y = 9
3y = x + 9
y = 1/3x + 3
Now we know the slope of the original line to be 1/3. Since perpendicular lines have opposite and reciprocal slope, we know the new line to have a slope of -3. We can then use that along with the given point in point-slope form to find the equation.
y - y1 = m(x - x1)
y - 2 = -3(x + 3)
y - 2 = -3x - 9
y = -3x - 7
Answer:
Mr mehra's salary is 26250
Step-by-step explanation:
suppose,
Mr mehra's salary is x
so,
He spends in food = 30% of x
=(30/100) . x [x%=x/100]
= 30x/100
=3x/10
He spends in charity =10% of x
=10x/100
=x/10
Money left = 15750
so,
x = 3x/10 + x/10 + 15750
⇒x - 3x/10 - x/10 = 15750
⇒(10x-3x-x) /10 = 15750
⇒6x/10 = 15750
⇒6x=157500
⇒x = 157500/6
⇒x = 26250
∴Mr mehra's salary is 26250