C
If you plug in the values in that equation, it works.
Answer:
The average value of
over the interval
is
.
Step-by-step explanation:
Let suppose that function
is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of
over the interval
by algebraic handling:
![F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)](https://tex.z-dn.net/?f=F%285%29%20-%20F%283%29%20%2B%5BF%283%29-F%28-2%29%5D%20%3D%2040%20%2B%20%28-30%29)



The average value of
over the interval
is
.
It means that 15 times another number equals to your equation.
Answer:
your answer will be a. .12 minutes
Step-by-step explanation:
this is your answer because you will add .12 to .08 to get your answer
State the domain of the relation R{(-3,3), (1,1), (0,2),(1,-4),(5,-1)} and then State the range of the relation R={(-3,3), (1,1)
harina [27]
The range is the Y value and the Domain is the X value.