Answer:
A) TA
Step-by-step explanation:
A radius goes from the center of a circle to the outside edge.
RP connects two points on the outside edge of the circle without going through the center. This is not a radius.
TR connects two opposite points on the outside edge of the circle while going through the center. This is a diameter, not a radius.
GP connects two opposite points on the outside edge of the circle while going through the center. This is a diameter, not a radius.
TA connects the center of the circle to the outside edge. This is a radius.
So if we want to know the least amount, we first want to assume the other two games both had a score of 52, so we can say the last one had the least possible.
So if both got 52, the total points would be 104, for two games of 52 points. Since we want 141 points, we therefore want 37 more points to reach 141.
So the least amount of points a player could've scored in one of the games was 37.
Answer:
b
Step-by-step explanation:
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Answer:
Hence proved triangle ADE ≅ triangle BCE by Side Angle Side congruent property.
Step-by-step explanation:
Given:
AD ⊥ AB 
CD
BC ⊥ AB CD
AD = BC
∴ ∠ A = ∠ B = ∠ C = ∠ D =90°
∠ EDC = ∠ ECD
Solution
∠ C = ∠ BCE + ∠ ECD⇒ equation 1
∠ D = ∠ ADE + ∠ EDC⇒ equation 2
∠ C = ∠ D (given)
Substituting equation 1 and 2 in above equation we get
∠ BCE + ∠ ECD = ∠ ADE + ∠ EDC
But ∠ EDC = ∠ ECD (given)
∴ ∠ ADE = ∠ BCE
ED = EC (∵ base angles are same triangle is isosceles triangle)
Now, In Δ ADE and Δ BCE
AD =BC
∠ ADE = ∠ BDE
ED = EC
∴ By Side Angle Side congruent property
Δ ADE ≅ Δ BCE
