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mina [271]
4 years ago
5

What value of n solves the equation 3^n=1/81 ? = A. –243 B. –27 C. –4 D. 4

Mathematics
1 answer:
meriva4 years ago
8 0
The solution is n=-4.
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a triangle with vertices (0 0) (5 3) (10 1) is dilated with a center of dilation at the origin by a factor of 5. what are the ne
Anastasy [175]
Algebraic rule —-> (x,y)—->(5x,5y)

(0,0) —> 0,0
(5,3)—-> 25,15
(10,1)—->50,5
6 0
4 years ago
What is the answer plzzzzzzzzzzzzzzz I need help
Licemer1 [7]

Answer:

(11 + c) + 8

Step-by-step explanation:

<u>Step 1</u>

The question says <em>"11 + Carlos's score (represented with a c)"</em>.

Hence: 11 + c

<u>Step 2</u>

The question says <em>"eight more than 11 + Carlos's score"</em>.

Hence: (11 + c) + 8

3 0
3 years ago
Read 2 more answers
Given two regular shapes, find the sum of the pink angles
son4ous [18]

Answer:

180

Step-by-step explanation:

that is my answer it will help you

4 0
3 years ago
Angela decides to recycle a large oatmeal container by using it to hold a friends birthday gift. Then she wraps the container in
Deffense [45]

Answer:

D. 135.37 in²

Step-by-step explanation:

We have that the gift paper consists of two circles and a square.

Thus, we will need to find the area of the circles and the square.

Now, as the diameter of the circle = 4 inches

So, the radius of the circle = \frac{4}{2} = 2 inches

Since, the area of a circle = \pi r^{2}

This implies that area of the two circles = 2\times \pi r^{2}

i.e. Area of the circles =  2\times \pi 2^{2}

i.e. Area of the circles =  8\pi

i.e. Area of the two circles = 25.133 in²

Further, one side of the square = 10.5 inches

Thus, the area of the square = side^{2}

i.e. Area of the square = 10.5^{2}

i.e. Area of the square = 110.25 in²

So, the overall area of the gift paper = 25.133 + 110.25 = 135.37 in².

Hence, the amount of paper used by Angela is 135.37 in².

7 0
3 years ago
1)
Ostrovityanka [42]
◆ Straight Lines ◆

Heya !

1) \: line \: is \: passing \: through \:points \: (5,7) \: and \: (6,8) \\ \\ slope \: of \: line \: = \frac{(y2 - y1)}{(x2 - x1)} \\ \\ slope \: = \: \frac{(8 - 7)}{(6 - 5)} = \: 1 \\ \\ equation \: of \: line \: = \: (y - y1) \: = m (x - x1) \\ \\ equation \: of \: line \: =( y - 7) = 1(x - 5) \\ \\ equation \: of \: line \: - \\ x - y + 2 = 0 \: ans. \\ \\ \\ 2) \: line \: is \: passing \: through \: ( - 3,6) \: and \: ( 3, - 6) \\ \\ slope \: of \: line \: = \frac{(y2 - y1)}{(x2 - x1)} \\ \\ slope \: of \: line \: = \frac{( - 6 - 6)}{(3 - ( - 3))} = - 2 \\ \\ equation \: of \: line = (y - y1) = m(x - x1) \\ \\ equation \: of \: line \: = (y - 6) = - 2(x + 3) \\ \\ equation \: of \: line \: - \\ 2x + y = 0 \: ans. \\ \\ hope \: it \: helps \: you :)

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8 0
3 years ago
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