The balanced net equation for
BaCl2 (aq) + H2SO4(aq) → BaSO4(s) + HCl (aq) is
Ba^2+(aq) +SO4^2- → BaSO4 (s)
<u><em>Explanation</em></u>
Ionic equation is a chemical equation in which electrolytes in aqueous solution are written as dissociated ions.
<u>ionic equation is written using the below steps</u>
Step 1: <em>write a balanced molecular equation</em>
BaCl2 (aq) +H2SO4 (aq)→ BaSO4(s) +2HCl (aq)
Step 2: <em>Break all soluble electrolytes in to ions</em>
= Ba^2+ (aq) + 2Cl^-(aq) + 2H^+(aq) + SO4^2-(aq)→ BaSO4(s) + 2H^+(aq) +2Cl^- (aq)
step 3: <em>cancel the spectator ions in both side of equation ( ions which do not take place in the reaction)</em>
<em> </em><em> =</em> 2Cl^- and 2H^+ ions
Step 4: <em>write the final net equation</em>
<em> Ba^2+(aq) + SO4^2-(aq)→ BaSO4(s</em><em>)</em>
Answer;
Molarity of NaOH is 0.80 M
Explanation;
The balanced equation for the reaction is;
2NaOH(aq) + H2SO4(aq = NaSO4(aq) +2 H2O (l)
Moles = concentration x volume
thus; 0.355M x 0.0282L= 0.01 moles of H2SO4.
Using the mole ratio;
Moles of NaOH = Moles of H2SO4 ×2
= 0.02 Moles
Therefore; moles of NaOH = 0.02 moles
But; Concentration = moles / volume
Thus; Concentration of NaOH = 0.02 / 0.025L
= 0.8M
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2H(+) + SO4(2-) + Ca(2+) + 2I(-) -> CaSO4(s) + 2H(+) + 2I(-)
The signs in brackets are the subscripts for the charge of the ion. This is the complete ionic equation. The net ionic equation is:
Ca(2+) + SO4(2-) -> CaSO4
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