All categories

2 years ago

write a balanced net ionic equation for the following reaction: BaCl2(aq) + H2SO4 (aq) -- BaSO4(s) + HCl (aq)

2 answers:

6 0

BaCl2 + H2SO4 ---> BaSO4 + HCl
It's balanced ionic equation would be:

BaCl2 + H2SO4 ---> BaSO4 + 2HCl

Hope this helps!

Fudgin [204]2 years ago

3 0

The balanced net equation for

BaCl2 (aq) + H2SO4(aq) → BaSO4(s) + HCl (aq) is

Ba^2+(aq) +SO4^2- → BaSO4 (s)

Explanation

Ionic equation is a chemical equation in which electrolytes in aqueous solution are written as dissociated ions.

ionic equation is written using the below steps

Step 1: write a balanced molecular equation

BaCl2 (aq) +H2SO4 (aq)→ BaSO4(s) +2HCl (aq)

Step 2: Break all soluble electrolytes in to ions

= Ba^2+ (aq) + 2Cl^-(aq) + 2H^+(aq) + SO4^2-(aq)→ BaSO4(s) + 2H^+(aq) +2Cl^- (aq)

step 3: cancel the spectator ions in both side of equation ( ions which do not take place in the reaction)

 = 2Cl^- and 2H^+ ions

Step 4: write the final net equation

 Ba^2+(aq) + SO4^2-(aq)→ BaSO4(s)

You might be interested in

true or false electrical energy is the amount of energy that contains an object due to the kinetic energy?

yuradex [85]

The answer to this question would be true.

4 0

2 years ago

Scientists have categorized trees based on whether they keep or lose their leaves each year. Another logical way to categorize t

Zolol [24]

Answer:

Explanation:

I think but it is an better attempt than the other guy answer.

5 0

2 years ago

Use the reaction given below to solve the problem that follows: Calculate the mass in grams of aluminum oxide produced by the re

bearhunter [10]

Answer: 28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} Al=\frac{15.0g}{27g/mol}=0.556moles$

The balanced chemical equuation is:

$4Al+3O_2\rightarrow 2Al_2O_3$

According to stoichiometry :

4 moles of $Al$ produce == 2 moles of $Al_2O_3$

Thus 0.556 moles of $Al$ will produce= $\frac{2}{4}\times 0.556=0.278moles$ of $Al_2O_3$

Mass of $Al_2O_3=moles\times {\text {Molar mass}}=0.278moles\times 102g/mol=28.4g$

Thus 28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal.

7 0

2 years ago

PLEASEE ANSWERRR FASTTT

IceJOKER [234]

Answer:

last one

Explanation:

The elements classified as metalloids are boron, silicon, germanium, arsenic, antimony, tellurium, and polonium.

8 0

3 years ago

Read 2 more answers

What are the molarity and osmolarity of a 1-liter solution that contains half a mole of calcium chloride? How many molecules of

givi [52]

Answer:

Molarity = 0.5 M

Osmolarity = 0.5 x 2 = 1 Osmpl.

Molecules of Cl2 = 6.02 x $10^{23}$ / 4= 1.505 x $10^{23}$ no. of molecules

Explanation:

If we add half mole in 1L volume than molarity will obviously be 0.5 M.

The osmolarity is molarity multiplies by number of dissociates of solute that for CaCl2 are 2. So, 2 x 0.5 = 1

Half will be molecules of Ca and half will be of Cl2 for 0.5M.

6 0

3 years ago